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Tomtit [17]
3 years ago
8

How does static electricity apply to car paint application?

Physics
1 answer:
Talja [164]3 years ago
4 0

Answer:

For electrostatic paint to be applied, the vehicle needs to be grounded and positively charged. This creates a magnetic attraction to the negatively charged paint. Due to this charge, when the paint leaves the nozzle, it is attracted to the vehicle's charge and will stick to it.

Explanation:

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Which of the following is an extremely reactive family of elements?
goblinko [34]

Answer:A) noble gases

Explanation: key word gas. if you fart it smells and other gases harm.

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3 years ago
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Four identical particles of mass 0.514 kg each are placed at the vertices of a 4.70 m x 4.70 m square and held there by four mas
Alona [7]

In order to solve the problem it is necessary to take into account the concepts related to the moment of inertia, and the center of mass of the object.

Our values are given by:

m = 0.514kg

I = 4.7m (each side)

A) For the case when the axis passes through the midpoints of opposite sidesand lies in the plane of the square. The formula is given by,

I = 4m (\frac{l}{2})^2\\I = 4*(0.514)(\frac{4.7}{2})^2\\I =  11.35kgm^2\\

B) For the case when the axis passes through the midpoint of one of the sides and is perpendicular to the plane of the square. The formula is given by,

I = 2m(\frac{l}{2})^2+2m(\frac{l}{2}^2+l^2)\\I = 2*(0.514)*(\frac{4.7}{2})^2+2*(0.514)*((\frac{4.7}{2})^2+4.7^2)\\I = 34.06Kgm^2

C) For the case when the axis lies in the plane of square f passes through two diagonally opposite particles,

I = \frac{1}{2}*l^2

I = \frac{1}{2}*(4.7)^2

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3 years ago
A marble is dropped off the top of a building. Find it's velocity and how far below to its dropping point for the first 10 secon
WINSTONCH [101]

1) velocity: 98 m/s downward

Explanation:

The marble moves by uniformly accelerated motion, with constant acceleration a=g=-9.8 m/s^2 directed towards the ground. Therefore, its velocity at time t is given by:

v(t)=v_0 +at

where

v_0 = 0 is the initial velocity

a=g=-9.8 m/s^2 is the acceleration

t is the time

Substituting t = 10 s, we find:

v(10 s)=0+(-9.8 m/s^2)(10 s)=-98 m/s

And the negative sign means the direction of the velocity is downward.


2) Distance covered: 490 m

The distance covered in an uniformly accelerated motion can be found with the formula:

S=\frac{1}{2}at^2

where

a=-9.8 m/s^2 is the acceleration

t is the time

Substituting t=10 s, we find

S=\frac{1}{2}at^2=\frac{1}{2}(-9.8 m/s^2)(10 s)^2=-490 m

And the negative sign means the displacement is below the dropping point.

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3 years ago
What are newtons laws and their description
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This may help

https://www.britannica.com/science/Newtons-laws-of-motion

But I don't know

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What is the measure of how much a material resists the formation of an electric field?
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