Explanation:
A wave having a frequency of 200 Hz means that 200 such waves pass through a point per second.
Answer:
The answer is %pearlite = 0.06%
Explanation:
according to the exercise we have that the percentage is 1.88% C, therefore, the percentage of perlite is equal to:
%pearlite = (B*C)/(A*C) = (2-1.88)/(2-0) = 0.06%
The percentage of cementite is equal to:
%cementite = (1.88-0)/(2-0) = 0.94%
Answer:
The maximum amplitude (
) will be 7.96 V.
Explanation:
We know, for distortion free operation, the slew rate (S) of an OPAMP is written as

where '
' is the highest frequency signal.
Therefore, from the above equation we can write,

Answer:
Time taken, 
Explanation:
It is given that, a small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal circle so that the thread’s trajectory describes a cone as shown in attached figure.
From the figure,
The sum of forces in y direction is :


Sum of forces in x direction,

.............(1)
Also, 
Equation (1) becomes :

...............(2)
Let t is the time taken for the ball to rotate once around the axis. It is given by :

Put the value of T from equation (2) to the above expression:


On solving above equation :

Hence, this is the required solution.
Answer:
Student 2 protons and valence electrons