The average kinetic energy of an atom in helium gas at temperature T is given by,
K.E=
here, K is botzmann constant =1.38×10⁻²³ m² kg s⁻² K⁻¹
Given, K.E= 6.21×10⁻²¹ J
Substituting the values,
T= 300 K
Therefore, at temperature 300 K the average kinetic energy of the atom in helium gas is 6.21×10⁻²¹ J.
Oceanic, Crust, Geolific, techtonic
Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880
Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000
Lost Energy = 5880 - 3000 = 2880 J
In short, Your Answer would be 2880 Joules
Hope this helps!
I would say downstream since the stream can push your boat, then you would have momentum and would just have to row towards the land.
Answer:
option c is correct
Explanation:
we know that time rate of change of velocity is called acceleration
so a=v/t
a=12/4
a=3m/s²
