Calculate the amount of solute needed for 1000 ml of 15% sodium thiosulfate

1 answer:

7 0

15% = 15 grams of solute in 100 mL solution

15 g --------------- 100 mL
?? ------------------ 1000 mL

1000 x 15 / 100 =

15000 / 100 => 150 g of solute

hope this helps!

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Answer:

CaS, CaBr₂, VBr₅, and V₂S₅.

Explanation:

The ionic compound should be neutral; the overall charge of it is equal to zero.

Binary ionic compound is composed of two different ions.

Ca²⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.

CaS can be formed via combining Ca²⁺ with S²⁻ to form the neutral binary ionic compound CaS.

CaBr₂ can be formed via combining 1 mole of Ca²⁺ with 2 moles of Br⁻ to form the neutral binary ionic compound CaBr₂.

V⁵⁺ can combined with either Br⁻ or S²⁻ to form binary ionic compounds.

V₂S₅ can be formed via combining 2 moles of V⁵⁺ with 5 moles of S²⁻ to form the neutral binary ionic compound V₂S₅.

VBr₅ can be formed via combining 1 mole of V⁵⁺ with 5 moles of Br⁻ to form the neutral binary ionic compound VBr₅.

So, the empirical formula of four binary ionic compounds that could be formed is: CaS, CaBr₂, VBr₅, and V₂S₅.

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Consider the reaction: 2HI(g) ⇄ H2(g) + I2(g). It is found that, when equilibrium is reached at a certain temperature, HI is 35.

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Answer:

Kc = 0.075

Explanation:

The dissociation (α) is the initial quantity that ionized divided by the total dissolved. So, let's calling x the ionized quantity, and M the initial one:

α = x/M

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$Kc = \frac{[H2]*[I2]}{[HI]^2}$