Nitrogen fixation is the process that makes atmospheric nitrogen available to plants by mutualistic and free-living bacteria. The process is undertaken by the rhizobium bacteria that live in root roots of plants such as legumes. The mutualistic relationship is that the plant supplies the bacteria with a habitat in which to live, water, and nutrients, and the bacteria supply nitrogen for making plant proteins.
To overcome the forces of attraction
intermolecular forces of attraction for the liquids and gases
Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
Ira is working in a lab with a unknown solution. when he inserts the electrical conductivity tester in the in known, the bulb begins to glow brightly. which of these would best describe the unknown liquid ?
A) It contains polar molecules that conduct electricity.
B) The water that the solid is dissolved in conducts electricity.
C) It contains a ionic compound that conducts electricity in solution.
D) It contains a covalent compound that conducts electricity in solution.
ANSWER:
C) It contains a ionic compound that conducts electricity in solution.
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Answer:
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Explanation:
Step 1: Obtain the mass of each element present in grams. Element % = mass in g = m.
Step 2: Determine the number of moles of each type of atom present. ...
Step 3: Divide the number of moles of each element by the smallest number of moles. ...
Step 4: Convert numbers to whole numbers.
