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Elodia [21]
3 years ago
5

Which formula represents hydrofluoric acid? HFO H2F HFO 4 HF

Chemistry
2 answers:
vovangra [49]3 years ago
5 0
I believe it’s HF :)
natulia [17]3 years ago
3 0

Answer:

it's HF

Explanation:

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Determine if these molecules and ion are polar.
Colt1911 [192]

Answer:

a. Polar

b. Polar

c. Non-polar

d. Non-polar

Explanation:

a. H_3O^+, hydronium cation contains a positive charge. Just as any other ion, it is polar, as it has a net charge.

b. H_2S has the same shape as water. There are two lone pairs on sulfur atom which produce an overall dipole moment in this molecule, the bent structure is polar.

c. PCl_5 is non-polar, as the central atom, phosphorus, doesn't contain any lone pairs, all the dipole moments cancel out: two dipole moments in the vertical plane, P-Cl, and three P-Cl dipoles in the horizontal plane within a trigonal bipyramidal shape.

d. CF_4 is non-polar, since it's a tetrahedral molecule with no lone pairs on carbon atom, all four C-F dipole moments cancel out to yield a net 0 dipole moment.

3 0
3 years ago
Is a burning log an exothermic or endothermic event if the log is the system?
ziro4ka [17]
Yes it is a exothermic reaction.
7 0
3 years ago
Read 2 more answers
Convert 213.62 grams of xenon gas at STP to L.
jolli1 [7]

Answer: The coefficient is 3.645

The exponent is 1

There are 4 significant digits

The rightmost significant figure is 5

Explanation:

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example : 5000 is written as 5.0\times 10^3

According to avogadro's law, 1 mole of every gas contains avogadro's number 6.023\times 10^{23} of particles, occupy 22.4 L at STP and weighs equal to its molecular mass.

131.29 g of Xe occupy = 22.4 L at STP.

Thus 213.62 g of Xe occupy = \frac{22.4}{131.29}\times 213.62=36.45L at STP.

Scientific notation = 3.645\times 10^1L

The coefficient is 3.645

The exponent is 1

There are 4 significant digits

The rightmost significant figure is 5

4 0
3 years ago
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0°c is 4.48. what is the value of ka for hbro?
elena-14-01-66 [18.8K]

The solution would be like this for this specific problem:

Given:

 

pH of a 0.55 M hypobromous acid (HBrO) at 25.0 °C =  4.48

 

[H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-] <span>

Ka = (3.31 x 10^-5)^2 / 0.55 = 2 x 10^-9</span>

 

To add, Hypobromous Acid does not require acid adjustment, which is necessary for chlorine-based product and is stable and effective in pH ranges of 5-9.<span>

</span>Hypobromous Acid combines with organic compounds to form a bromamine. Chlorine also combines with the same organic compounds to form a chloramine. <span>It is also one of the least expensive intervention antimicrobial compounds available.</span>

8 0
3 years ago
Read 2 more answers
This is not a homework question
Dovator [93]
What state you live in? because I know someone who does it for free
8 0
3 years ago
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