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miss Akunina [59]
3 years ago
5

Given that mass was lost from the copper (ii) carbonate hydroxide hydrate during heating, in this decomposition reaction, how ma

ny moles of solid product were produced? the molar mass of the solid product is 79.545 g/mol (number of moles = mass (g) / molar mass (g/mol)).
Chemistry
1 answer:
Bad White [126]3 years ago
7 0
The thermolysis of hydrate of the copper (II) hydroxycarbonate:

xCuCO₃·yCu(OH)₂·zH₂O → (x+y)CuO + xCO₂ + (y+z)H₂O

1 mol xCuCO₃·yCu(OH)₂·zH₂O → (x+y) mol CuO

for example, if x=y=1 ⇒ n(CuO)=2 mol
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ss7ja [257]

Answer: The new pressure will be 1.42 atm

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

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P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=1.18atm\\T_1=4^0C=(4+273)K=277K\\P_2=?\\T_2=60^0C=(60+273)K=333K

Putting values in above equation, we get:

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STALIN [3.7K]
3Mg + N₂= Mg₃N₂
n(Mg)=12,2g÷<span>24,4g/mol=0,5mol-limiting reagent
</span>n(N₂)=5,16g÷28g/mol=0,18mol
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3 years ago
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