Answer:
Explanation:
The energy, E, from a capacitor, with capacitance, C, and voltage V is:
If we increase the Voltage, the Energy increase also:
The voltage difference:
Actually, they're not. There's a group of stars and constellations arranged
around the pole of the sky that's visible at any time of any dark, clear night,
all year around. And any star or constellation in the rest of the sky is visible
for roughly 11 out of every 12 months ... at SOME time of the night.
Constellations appear to change drastically from one season to the next,
and even from one month to the next, only if you do your stargazing around
the same time every night.
Why does the night sky change at various times of the year ? Here's how to
think about it:
The Earth spins once a day. You spin along with the Earth, and your clock is
built to follow the sun . "Noon" is the time when the sun is directly over your
head, and "Midnight" is the time when the sun is directly beneath your feet.
Let's say that you go out and look at the stars tonight at midnight, when you're
facing directly away from the sun.
In 6 months from now, when you and the Earth are halfway around on the other
side of the sun, where are those same stars ? Now they're straight in the
direction of the sun. So they're directly overhead at Noon, not at Midnight.
THAT's why stars and constellations appear to be in a different part of the sky,
at the same time of night on different dates.
Answer:
a) P' = P_original, b) P ’= P_original + ρ g Δh
Explanation:
The expression for nanometric pressure is
P = ρ g h
where ρ is the density of the liquid and h is the height
a) we change the radius of the barrel, but keeping the same height
as the pressure does not depend on the radius it remains the same
P' = P_original
b) We change the barrel height
h ’≠ h
we substitute in the equation
P ’= ρ g h’
h ’= h + Δh
P ’= ρ g (h + Δh)
P ’= (ρ g h) + ρ g Δh
P ’= P_original + ΔP
In this case, the pressure changes due to the new height,
*if it is higher than the initial one, the pressure increases
*if the height is less than the initial one, the pressure is less
Answer:
q = 7.542 x 10⁻⁷ C = 754.2 nC
Explanation:
The Coulomb's Law gives the magnitude of the force of attraction or repulsion between two charges:
F = kq₁q₂/r²
where,
F = Force of attraction or repulsion = 0.2 N
k = Coulomb's Constant = 9 x 10⁹ N m²/C²
r = distance between charges = 16 cm = 0.16 m
q₁ = magnitude of 1st charge
q₂ = magnitude of 2nd charge
Since, both charges are said to be equal here.
q₁ = q₂ = q
Therefore,
0.2 N = (9 x 10⁹ N m²/C²)q²/(0.16 m)²
(0.2 N)(0.16 m)²/(9 x 10⁹ N m²/C²) = q²
q = √(5.88 x 10⁻¹³ C²)
<u>q = 7.542 x 10⁻⁷ C = 754.2 nC</u>
D.) In order to calculate both of them, we must know the "FORCE" on the system.
