Explanation:
We know that,
Energy =
.......... (1)
and, Energy =
............ (2)
Now, equating both equations (1) and (2) as follows.
= ![k \frac{qQ}{r}](https://tex.z-dn.net/?f=k%20%5Cfrac%7BqQ%7D%7Br%7D)
v = ![\sqrt{\frac{2kqQ}{r \times m}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B2kqQ%7D%7Br%20%5Ctimes%20m%7D%7D)
= ![\sqrt{\frac{2 \times 9 \times 10^{9} \times 1.6 \times 10^{-19} \times 1.8 \times 10^{-15}}{0.017 m \times 9.109 \times 10^{-31}}}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B2%20%5Ctimes%209%20%5Ctimes%2010%5E%7B9%7D%20%5Ctimes%201.6%20%5Ctimes%2010%5E%7B-19%7D%20%5Ctimes%201.8%20%5Ctimes%2010%5E%7B-15%7D%7D%7B0.017%20m%20%5Ctimes%209.109%20%5Ctimes%2010%5E%7B-31%7D%7D%7D)
= ![\sqrt{336.62 \times 10^{6}}](https://tex.z-dn.net/?f=%5Csqrt%7B336.62%20%5Ctimes%2010%5E%7B6%7D%7D)
=
m/s
or, = 18 km/s
Thus, we can conclude that initial speed the electron must have in order to reach an infinite distance from the sphere and have zero kinetic energy when it gets there is 18 km/s.
Answer: 51.4 g of NaClO will be produced.
Explanation:
To calculate the moles :
![\text{Moles of} Cl_2=\frac{48.9g}{71g/mol}=0.69moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%7D%20Cl_2%3D%5Cfrac%7B48.9g%7D%7B71g%2Fmol%7D%3D0.69moles)
![\text{Moles of} NaOH=\frac{54.2g}{40g/mol}=1.4moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%7D%20NaOH%3D%5Cfrac%7B54.2g%7D%7B40g%2Fmol%7D%3D1.4moles)
According to stoichiometry :
1 moles of
require = 2 moles of ![NaOH](https://tex.z-dn.net/?f=NaOH)
Thus 0.69 moles of
will require=
of ![NaOH](https://tex.z-dn.net/?f=NaOH)
Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent.
As 1 mole of
give = 1 mole of ![NaClO](https://tex.z-dn.net/?f=NaClO)
Thus 0.69 moles of
give =
of ![NaClO](https://tex.z-dn.net/?f=NaClO)
Mass of ![NaClO=moles\times {\text {Molar mass}}=0.69moles\times 74.5g/mol=51.4g](https://tex.z-dn.net/?f=NaClO%3Dmoles%5Ctimes%20%7B%5Ctext%20%7BMolar%20mass%7D%7D%3D0.69moles%5Ctimes%2074.5g%2Fmol%3D51.4g)
Thus 51.4 g of NaClO will be produced
Answer:
- Not balanced.
- Reactants: Zn and HCI
.
- Products: ZnCl₂ and H₂.
- Substitution reaction.
Explanation:
Hello,
In this case, for the given reaction:
Zn + HCI → ZnCl₂ + H₂
We can see that it is not balanced due to the fact that at the left side we have one hydrogen atom whereas at the right side two, taking into account the number must be same as well as chlorine. Thus, in order to balance we write:
Zn + 2HCI → ZnCl₂ + H₂
And that is enough. Moreover, we can see that the chemical species at the left side of the equation are the reactants and those at the right side the products, thus we have:
Reactants: Zn and HCI
.
Products: ZnCl₂ and H₂.
Finally, since we can see that the chlorine is at the reactants with hydrogen, but at the end with the zinc, and the initial zinc is alone as well as the yielded hydrogen we can infer this is a substitution reaction.
Best regards.
Answer:ionic bond
Lithium becomes +ve while FL becomes-ve
Explanation:bond btwn a metal and a none metal is called an ionic bond
Li loses one therefore it's+ve FL gains becoming -ve
The atomic number for iodine (I) = 53
The electron for I is:
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵
Now, among the noble gases, Krypton (Kr) has an atomic number 36. Thus we can write:
I = [1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ ] 5s² 4d¹⁰ 5p⁵
I = [Kr] 5s² 4d¹⁰ 5p⁵
(or)
I = [Kr] 4d¹⁰ 5s² 5p⁵