MgCl₂)= Mg²⁺ + 2Cl⁻
V(MgCl₂)=285cm³=0,285dm³
c(MgCl₂)=0,015 mol/dm³
n(MgCl₂)=c·V= 0,015 mol/dm³ · 0,285dm³ = 0,0042 mol
n(Mg²⁺)=n(MgCl₂)=0,0042 mol
n(Cl⁻)=2n(MgCl₂)=0,0084 mol
Answer:
D = 4 g/mL
General Formulas and Concepts:
Density = Mass over Volume
Explanation:
<u>Step 1: Define</u>
m = 100 g
V = 25 mL
D = unknown
<u>Step 2: Find D</u>
- Substitute: D = 100 g/25 mL
- Evaluate: D = 4 g/mL
Answer:
See the answe below, please.
Explanation:
In the stomach, during digestion there are two types of:
-Mechanics: the degradation of food occurs, distension of the stomach walls is performed when they arrive, producing the Chyme.
Chemistry: through the participation of enzymes (pepsin activated by hydrochloric acid, which digests proteins in shorter amino acid chains and; gastric lipase that breaks fat giving glycerin products and fatty acids)
