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3 years ago

Which property decreases when the element in group 17 are considered in order of increasing atomic number

2 answers:

4 0

Electronegativity decreases as you go down a period, aka increasing the atomic number along a specific group, in this case, group 17.

mart [117]3 years ago

3 0

Electromagnetically decreases when the elements are considered in order of increasing atomic number.
In this problem they were asking regarding group 17.
Final answer: Electromagnetically

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Is Actinium Metal, Non-Metal ,or Semi-Metal?

SCORPION-xisa [38]

Metal
On the periodic table its atomic number is 89
The Semi-metals aka the metalloids are atomic umbers 5,14,32,33,51,52,and 85

The Metals are everything that is located to the left of the metalloids excluding Hydrogen(H) and Helium (He)
Everything to the right of the metalloids are non-metals including Hydrogen (H) and Helium (He)

4 0

4 years ago

What is it called when an atom completes its outer shell of electrons (8)?

Paraphin [41]

Answer:

valence shell

Explanation:

. This outermost shell is known as the valence shell, and the electrons found in it are called valence electrons.

4 0

4 years ago

What volume of o2 is needed to react fully with 720. Ml of nh3

Galina-37 [17]

Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.

<h3>What is volume?</h3>

Volume is the area occupied by the substance and is the ratio of the mass to the density.

At STP, 1 mole of gas occupies 22.4 L of volume

Given,

Volume of ammonia reacted = 0.720 L

The combustion reaction is shown as,

$\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O$

From the stoichiometry of the reaction, it can be said that,

$(4 \times 22.4)$ L of ammonia reacts with $(5 \times 22.4)$ L of oxygen gas.

So, 0.720 L of ammonia will react with:

$\dfrac{ (5 \times 22.4)}{(4 \times 22.4)} \times 0.720 = 0.9 \;\rm L$

Therefore, the volume of oxygen required is 900 mL.

Learn more about volume here:

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6 0

3 years ago

A student dissolves 6.2g of aniline c6h5nh2 in 350.ml of a solvent with a density of 1.04/gml . the student notices that the vol

Troyanec [42]

Answer : The correct answer for molarity = 0.19 $\frac{mol}{L}$ and Molality = 0.18 $\frac{mol}{Kg}$ .

Given : Mass of aniline = 6.2 g

Volume of solvent = 350 mL Density of solvent = 1.04 g/mL

1) Molarity : It is defined as number of moles of solute present in Litre of solution . It is expressed as :

$Molarity(M) = \frac{moles of solute(mole)}{volume of solution (L)}$ \

Molairty can be found in following steps :

Step 1 : To calculate mole :

Mole of solute can be calculate using mole formula :

$Mole of solute = \frac{given mass of solute (g)}{molar mass of solute\frac{g}{1 mol}}$

Molar mass of aniline (C₆H₅NH₂) = 93.13 $\frac{g}{1 mol}$

Mass of aniline = 6.2 g

Plugging values in mole formula :

$Mole = \frac{6.2 g}{93.13 \frac{g}{1 mol}}$

Mole = 0.0665 mol

Step 2 : To find volume of solution

Volume of solution = volume of solute + volume of solution

Since addition of aniline does not change final volume , so volume of solvent = volume of solution. Since volume is given in mL , so it need to be converted to L .

1 L = 1000mL

$Volume of solution = \frac{350 mL}{1000mL} * 1 L$