Given :
Some compounds :
.
To Find :
Which of the following compounds has the most deshielded protons .
Solution :
Deshielded means nucleus whose chemical shift has been increased due to removal of electron density, magnetic induction, or other effects .
In simple words deshielding means the ability to shift protons .
Now , among Cl , I , Br and H . Cl is the most electron negative .
Therefore , deshielding will be more in 
.
Hence , this is the required solution .
Answer:
a rapidly flowing river discharges into the ocean where tidal currents are weak.
Explanation:
The force of the river pushing fresh water out to sea rather than tidal currents transporting seawater upstream determines the water circulation in these estuaries.
The Boiling Point of 2-methylpropane is approximately -11.7 °C, while, Boiling Point of <span>2-iodo-2-methylpropane is approximately 100 </span>°C.
As both compounds are Non-polar in nature, So there will be no dipole-dipole interactions between the molecules of said compounds.
The Interactions found in these compounds are London Dispersion Forces.
And among several factors at which London Dispersion Forces depends, one is the size of molecule.
Size of Molecule:
There is direct relation between size of molecule and London Dispersion forces. So, 2-iodo-2-methylpropane containing large atom (i.e. Iodine) experience greater interactions. So, due to greater interactions 2-iodo-2-methylpropane need more energy to separate from its partner molecules, Hence, high temperature is required to boil them.
Answer:
Unsaturated
Explanation:
In order to successfully answer this question, we need to think about the solubility of solutes in specific solvents, typically water.
- A solution is considered to be unsaturated if at a given temperature and volume of water we may still add more solute and it will dissolve;
- A solution is considered to be saturated if at a given temperature and volume of water we have a maximum amount of solute dissolved and trying to add more solute results in undissolved crystals that can be seen in the solution;
- A solution is considered to be oversaturated (or supersaturated) i at a given temperature and volume of water we exceeded the maximum amount of a solute that could possibly dissolve.
In this case, if we can continue to add more solute to a solution and the solute dissolves, we may state that we are still at a point in which we have an unsaturated solution.
