Answer:
now i dont know if this is the thing your asking but a negative plus a negative is a positive.
Answer:
![{84mm}^{2}](https://tex.z-dn.net/?f=%20%7B84mm%7D%5E%7B2%7D%20)
Step-by-step explanation:
Area of square= l×l
Area of square= 6mm × 6mn
Area if square = 36 mm²
Area of triangle 1= ½b ×h
Area of triangle 1= ½ (6mm)(8mm)
Area of triangle 1 = 24 mm²
Area of triangle 2 is the same as area of traingle 1 because they have the same base and hight
: . area of triangles is 48mm²
Area of the figure= Area of square + Area of triangles
A of figure = 36+48
A of figure = 84 mm²
Option 2
Use trapezium formula
Area of trapezium= (a+b)/2 * h
a=6 mm (base)
b=8+6=14 mm (Base)
h= 6mm (height)
![area \: of \: trapezium = ( \frac{6 + 14}{2} )(6) \\ = 60mm ^{2}](https://tex.z-dn.net/?f=area%20%5C%3A%20of%20%5C%3A%20trapezium%20%3D%20%28%20%5Cfrac%7B6%20%2B%2014%7D%7B2%7D%20%29%286%29%20%5C%5C%20%20%3D%2060mm%20%5E%7B2%7D%20)
Therefore the area of triangle= 24mm² as calculated in option 1
Area of the figure= Area of trapezium +Area of triangle
Area of figure = 60+24
= 84 mm²
Answer:
4 3/10
Step-by-step explanation:
3 3/8-1 1/5+17/8
=27/8-1 1/5+17/8
=27/8-6/5+17/8
=87/40+17/8
=43/10
=4 3/10
(2x+23)+(9x-5)=95
11x+18=95
x= 95-18/11
x=7
therefore substituting value of x in the given equations of angles:
angle ABD = 2(7)+23=37°
angle DBC = 9(7)-5= 58° Answer
to verify = 37°+58°= 95° ( which was given)