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Pavel [41]
3 years ago
12

Which is true about the potential energy of the reactants in this reaction pathway

Chemistry
2 answers:
MaRussiya [10]3 years ago
7 0

it is equal to the potential energy of the products

irga5000 [103]3 years ago
3 0

Answer: it is equal to the potential energy of the products

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Which statements are true about reversible reactions?
umka21 [38]

Answer:

Reversible reactions exhibit the same reaction rate for forward and reverse reactions at equilibrium.

Reversible reactions exhibit constant concentrations of reactants and products at equilibrium

Explanation:

A reversible reaction is a reaction that can proceed in both forward and backward direction.

Equilibrium is attained in a chemical system when there is no observable change in the properties of the system.

At equilibrium, a reversible reaction is occurring in at same rate. That is, the forward and backward reaction is occurring at the same rate. As the rate of the forward and backward reaction remains the same, the concentrations of the reactants and products will also be the same in order for the equilibrium to be maintained.

5 0
3 years ago
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What is electron configuration of oxygen in its excited state​
timofeeve [1]

Answer:

1 {s}^{2} 2 {s}^{2} 2 {p}^{4}

OR

2 : 6

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3 years ago
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Does anyone know how to do this? the solubility of barium carbonate, BaCO3, is 0.0100 g/L. Its molar mass is 197.3 g/mol. What i
g100num [7]
It's simple, just follow my steps.

1º - in 1 L we have 0.0100~g of BaCO_3

2º - let's find the number of moles.

\eta=\frac{m}{MM}

\eta=\frac{0.0100}{197.3}

\boxed{\boxed{\eta=5.07\times10^{-5}~mol}}

3º - The concentration will be

C=5.07\times10^{-5}~mol/L

But we have this reaction

BaCO_3\rightleftharpoons Ba^{2+}+CO_3^{2-}

This concentration will be the concentration of Ba^{2+}~~and~~CO_3^{2-}

K_{sp}=\frac{[Ba^{2+}][CO_3^{2-}]}{[BaCO_3]}

considering [BaCO_3]=1~mol/L

K_{sp}=[Ba^{2+}][CO_3^{2-}]

and

[Ba^{2+}]=[CO_3^{2-}]=5.07\times10^{-5}~mol/L

We can replace it

K_{sp}=(5.07\times10^{-5})*(5.07\times10^{-5})

K_{sp}\approx25.70\times10^{-10}

Therefore the K_{sp} is:

\boxed{\boxed{\boxed{K_{sp}\approx2.57\times10^{-11}}}}
4 0
3 years ago
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How much heat is required to raise the<br> temperature of 835g of water from 35.0°C to<br> 65.0°C?
Anna007 [38]

Answer:

25,050 calories.

Explanation:

A calorie is the amount of energy needed to raise the temperature of one gram of water 1 degree centigrade. If we are raising 835 grams of water 30 degrees then we multiply 835*30 to get 25,050 calories.

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Which of the following properties of an unknown substance would allow it to be classified as a pure substance ?
DanielleElmas [232]

D because that’s the only one that makes sense

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