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3 years ago

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A 0.45-g sample of aspirin is decomposed into its constituent elements and found to contain 0.27 g C, 0.020 g H, and 0.16 g O. C

alculate the mass percent compositions of C, H, and O in aspirin.

1 answer:

slamgirl [31]3 years ago

3 0

Answer:

Explanation:

mass % of C = 0.27/0.45*100 = 60%

mass % of H = 0.02/0.45*100 = 4.4%

mass % of O = 0.16/0.45*100 = 35.6%

Total = 60%+4.4%+ 35.6% = 100%

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The following image shows the Atomic level of an element. In the image, which of

svp [43]

Answer:

D. The cation will use a type II naming system

Explanation:

As the element becomes stable, Option D is NOT taking place. That means that as the element becomes stable, the cation will NOT use a type II naming system. This is because in Type II binary compounds, the metal is not found in either Group 1 or Group 2 on the periodic table. It is as a result of this that the cation will not use a type II naming system.

Group 1 and Group 2 elements make use of type I naming system because in Type I binary compounds, the metal is present.

Option D is the correct answer.

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3 years ago

Cyclohexane has a freezing point of 6.50 ∘C and a Kf of 20.0 ∘C/m. What is the freezing point of a solution made by dissolving 0

Elza [17]

Answer: $2.49^0C$

Explanation:

Depression in freezing point is:

$T_f^0-T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of solvent (cyclohexane) = $6.50^oC$

$k_f$ = freezing point constant of solvent (cyclohexane) = $20.0^oC/m$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

$w_2$ = mass of solute (biphenyl) = 0.771 g

$w_1$ = mass of solvent (cyclohexane) = 25.0 g

$M_2$ = molar mass of solute (biphenyl) =

Now put all the given values in the above formula, we get:

$(6.50-T_f)^oC=1\times (20.0^oC/m)\times \frac{(0.771g)\times 1000}{154\times (25.0g)}$

$(6.50-T_f)^oC=4.01$

$T_f=2.49^0C$

Therefore, the freezing point of a solution made by dissolving 0.771 g of biphenyl in 25.0 g of cyclohexane is $2.49^0C$

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3 years ago

Take your time please.

SIZIF [17.4K]

<h2>Answer:</h2>

1. Dependant Variable

2. Scientific Method

3. Data

4. Consistency

5. Metric Balance

6. Mean

7. Technology

8. Dependant Variable

9. Hypothesis

10. Spring Scale

<h2>Explanation:</h2>

<em>Hello! I hope this helped and please correct me if some are wrong. I did my research and matched them. Have a good one!</em>

<h2>(>‿◠)✌</h2>

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2 years ago

Read 2 more answers

A galvanic cell consists of a Al3 /Al half-cell and a standard hydrogen electrode. If the Al3 /Al half-cell standard cell functi

11111nata11111 [884]

Answer:

Explanation:

here is your answer:

3 0

3 years ago

What is the correct net ionic equation, including all coefficients, charges, and phases, for the following set of reactants? Ass

Nataly [62]

Answer:

Ba^2+(aq) + 2OH-(aq) + 2H+(aq) + SO4^2-(aq) → BaSO4(s) + 2H2O(l)

Explanation:

Step 1: Data given

the contribution of protons from H2SO4 is near 100 %.

Step 2: The unbalanced equation

.Ba(OH)2(aq) + H2SO4(aq) → BaSO4(s) + H2O(l)

Step 3: Balancing the equation

On the left side we have 4x H (2x in Ba(OH)2 and 2x in H2SO4). On the right side, we have 2x H (in H2O).

To balance the amount of H on both sides, we have to muliply H2O (on the right side) by 2.

Ba(OH)2(aq) + H2SO4(aq) → BaSO4(s) + 2H2O(l)

Step 4: The net ionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will.

Ba^2+(aq) + 2OH-(aq) + 2H+(aq) + SO4^2-(aq) → BaSO4(s) + 2H2O(l)

After canceling those spectator ions in both side, look like this:

Ba^2+(aq) + 2OH-(aq) + 2H+(aq) + SO4^2-(aq) → BaSO4(s) + 2H2O(l)

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3 years ago