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IRISSAK [1]
3 years ago
6

A scientist is studying a compound that includes nitrogen, carbon, oxygen, and hydrogen. Is the scientist studying an organic mo

lecule? Why or why not?
Chemistry
2 answers:
weqwewe [10]3 years ago
8 0

Answer: It is an organic molecule

Explanation:

In order for a molecule to be organic, it has to contain both carbon and hydrogen. The compound that the scientist is studying contains both.

GuDViN [60]3 years ago
4 0
A molecule of the kind normally found in living systems. Organic molecules are usually composed of carbon atoms in rings or long chains, to which are attached other atoms of such elements as hydrogen, oxygen, and nitrogen. yes this would be organic hope this helps!!
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A stack of 10 pennies weighing 26.55 grams is placed in a graduated cylinder containing water. The initial volume of water is 50
BigorU [14]
In order to determine the density of an item, we will need to determine its mass and volume. The standard unit for measuring mass in a lab is the gram. Think about liquids- what units do you typically report the volume of a liquid in? What about for a sugar cube, what volume is the most appropriate?
A regular object like a sugar cube can be measured with a ruler so we might report the volume in centimeters cubed (cm3). An irregular object like the plate pictured below can be measured by using a technique called volume by displacement. A liquid (typically water) is placed in a graduated cylinder and the volume of a liquid is measured. Then the irregular object is placed in the liquid and the volume is measured again. The change in volume is the irregular object’s volume. This measurement is often made using a graduated cylinder and recording a volume in Liters or milliliters (mL).
Figure 1. (a) Regular object of metal blocks with the same width, length, and height. (B) An irregular
7 0
3 years ago
7. How many chlorine atoms are in a 34.2 g sample of dichlorine pentoxide?
Reptile [31]

Answer:

The answer to your question is 1.36 x 10²³ atoms

Explanation:

Data

number of atoms = ?

mass of the sample = 34.2 g

Molecule = Cl₂O₅

Process

1.- Calculate the molar mass of Cl₂O₅

Cl₂O₅ = (35.5 x 2) + (16 x 5) = 71 + 80 = 151 g

2.- Calculate the atoms of Cl₂O₅

                     151 g of Cl₂O₅ ---------------- 6 .023 x 10²³ atoms

                       34.2 g of Cl₂O₅ ------------ x

                          x = (34.2 x 6.023 x 10²³) / 151

                          x = 1.36 x 10²³ atoms

4 0
3 years ago
Describes two uses of surfactants at least one must be something that was not described in the passage
Morgarella [4.7K]

Answer:

We don't have the passage.  A random sampling of surfactant uses includes:

  • removal of oily materials from objects (clothes and dishes)
  • forms remarkable structures called bubbles
  • Assists in forming emulsions (e.g., mayonaise and paints)

Explanation:

The structure of a surfactant makes one end of a molecule hydrophilic and the other end hydrophobic.  In water, they self-assemble into micelles, an arrangement in which the hydrophobic ends align towards the center, and the hydrophilic ends are pointed outwards to the water.  This self-assembly is apparant when bubbles are made.  The  molecules quickly align themselves such that the hyrophilic ends are oriented inwards towards a thin layer of water and the hydrophobic ends are pointed outward to the air.  This arrangement allows a mono-molecular sphere of water molecules to remain stable enough to float, reflect light, and please.  These same properties allow the inverse to occur.  Soap molecules surround a hydrophobic mass (e.g., the hamburger grease on your shirt) and solubilize it into small micelles which are then carried away in the surrounding water.

4 0
2 years ago
6) Which of these elements is a metal?<br> E) C<br> D) N<br> A) O<br> C) Ne<br> B) Ca
sertanlavr [38]

Answer:

Ca

Explanation:

It is on the left side of the periodic table where metals are located.

4 0
3 years ago
Read 2 more answers
By the reaction of carbon &amp; oxygen , a mixture of CO &amp;CO2 is obtained. What is the composition by mass of the mixture ob
Hatshy [7]
M(O₂)=20g
M(O₂)=32.0 g/mol
n(O₂)=20/32.0=0.625 mol

m(C)=12 g
M(C)=12.0 g/mol
n(C)=12/12.0=1.0 mol

   2C     +     O₂      →    2CO
1 mol    0.625 mol        1 mol
         0.625-0.5=0.125 mol

      2CO    +         O₂       →        2CO₂
0.250 mol       0.125 mol       0.250 mol

n(CO)=1 mol - 0.250 mol = 0.750 mol
M(CO)=28.0 g/mol
m(CO)=0.750*28.0=21.0 g

n(CO₂)=0.250 mol
M(CO₂)=44.0 g/mol
m(CO₂)=0.250*44.0=11.0 g
4 0
3 years ago
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