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nalin [4]
2 years ago
13

Which three items below represent compounds?

Chemistry
2 answers:
irina1246 [14]2 years ago
5 0

Answer:

Bases

NaCl

Acids

Explanation:

because compound consist of many atoms joined together.

Talja [164]2 years ago
4 0
The answer is bases, NaCal, and Acids hope it helped!
You might be interested in
2. A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine:2HI (g) H2(g)
Deffense [45]

Answer:

The value of Kp at this temperature is 7.44*10⁻³

Explanation:

Chemical equilibrium is established when there are two opposite reactions that take place simultaneously at the same speed.

For the general chemical equation for a homogeneous gas phase system:

aA + bB ⇔ cC + dD

where a, b, c and d are the stoichiometric coefficients of compounds A, B, C and D, the equilibrium constant Kp is determined by the following expression:

Kp=\frac{P_{C} ^{c} *P_{D} ^{d} }{P_{A} ^{a} *P_{B} ^{b} }

Where Px is the partial pressure of each of the components once equilibrium has been reached and they are expressed in atmospheres. The equilibrium constant Kp depends solely on temperature and is dimensionless.

In the case of the reaction:

2 HI (g) ⇔ H₂ (g) + I₂ (g)

the equilibrium constant Kp is determined by the following expression:

Kp=\frac{P_{H_{2} } *P_{I_{2} } }{P_{HI} ^{2} }

The system comes to equilibrium at 425 °C, and

  • PHI = 0.794 atm
  • PH2 = 0.0685 atm
  • PI2 = 0.0685 atm

Replacing:

Kp=\frac{0.0685*0.0685}{0.794^{2} }

Kp=7.44*10⁻³

<u><em>The value of Kp at this temperature is 7.44*10⁻³</em></u>

4 0
3 years ago
For the following electron-transfer reaction:
creativ13 [48]

Answer:

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

Explanation:

Main reaction: 2Ag⁺(aq) + Mn(s) ⇄ 2Ag(s) + Mn²⁺(aq)

In the oxidation half reaction, the oxidation number increases:

Mn changes from 0, in the ground state to Mn²⁺.

The reduction half reaction occurs where the element decrease the oxidation number, because it is gaining electrons.

Silver changes from Ag⁺ to Ag.

1. The oxidation half-reaction is: Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

2. The reduction half-reaction is: Ag⁺(aq) + 1e⁻ ⇄ Ag(s)  

To balance the hole reaction, we need to multiply by 2, the second half reaction:

Mn(s) ⇄ Mn²⁺(aq) + 2e⁻

(Ag⁺(aq) + 1e⁻ ⇄ Ag(s)) . 2

2Ag⁺(aq) + 2e⁻ ⇄ 2Ag(s)  

Now we sum, and we can cancel the electrons:

2Ag⁺(aq) + Mn(s) + 2e⁻ ⇄ 2Ag(s) + Mn²⁺(aq) + 2e⁻

4 0
3 years ago
Plz help soon? I’m confused
nata0808 [166]
Hi,
I think the answer is metric.
6 0
2 years ago
How many ATOMS of OXYGEN are there in the following compound
STatiana [176]
6 Atoms!
Mg = 1 atom.
O = 4 atoms.
A = 1 atom.
5 0
3 years ago
The ideal gas constant, R has several different values that could be used. Which quantity causes these differences? pressure tem
Blababa [14]

Answer : The correct option is, pressure.

Explanation :

The ideal gas equation is,

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

n = number of moles of gas

T = temperature of the gas

R = gas constant

The value of 'R' has several different values which are :

R=0.08205L.atm/mol.K

R=8.3145L.kPa/mol.K

R=8.3145J/mol.K 

R=1.987cal/mol.K

R=0.08314L.bar/mol.K

That means, the value of 'R' is different due the change in the pressure value and all the variables (temperature, volume and moles) are constant.

Hence, the correct option is, pressure.

3 0
3 years ago
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