Answer:
Specific cells within the gastric lining, known as chief cells, release pepsin in an inactive form, or zymogen form, called pepsinogen. By doing so, the stomach prevents the auto-digestion of protective proteins in the lining of the digestive tract.
Explanation:
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The particles are atoms, his theory is the atomic theory
Answer:
60 V
Explanation:
From;
Vs/Vp = Ns/Np
Where;
Vs = voltage in the secondary coil = 6V
Vp = voltage in the primary coil= ??
Ns = number of turns in the secondary coil = 9
Np= number of turns in the primary coil = 90
6/Vp = 9/90
Vp= 90 * 6/9
Vp= 60 V
C. 6, 1, 0, -1/2
Explanation:
The four quantum numbers are:
- Principal quantum number (n): this represents the energy level in which an orbital is located.
- Azimuthal quantum number gives the shape of the orbitals in subshells accommodating the electrons.
- Magnetic quantum number gives the number of spatial orientations or degeneracy of the orbitals in the subshells.
- Spin quantum number describes the spinning of an electron in either clockwise or anticlockwise directions.
To know the electron with the highest energy, we use the principal quantum number values.
n values takes whole numbers i.e n = 1,2,3,4,5,6,7.............
The higher the value, the higher the energy level.
From the given quantum numbers, C has the highest energy levels.
Learn more;
Quantum numbers brainly.com/question/9288609
#learnwithBrainly
Answer : The concentration of ![[Fe(SCN)]^{2+}](https://tex.z-dn.net/?f=%5BFe%28SCN%29%5D%5E%7B2%2B%7D)
is, 
Explanation :
When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is 
and 
is excess reagent.
First we have to calculate the moles of KSCN.
Moles of KSCN = Moles of 
= Moles of = 
Now we have to calculate the concentration of
![\text{Concentration of }[Fe(SCN)]^{2+}=\frac{\text{Moles of }[Fe(SCN)]^{2+}}{\text{Volume of solution}}](https://tex.z-dn.net/?f=%5Ctext%7BConcentration%20of%20%7D%5BFe%28SCN%29%5D%5E%7B2%2B%7D%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20%7D%5BFe%28SCN%29%5D%5E%7B2%2B%7D%7D%7B%5Ctext%7BVolume%20of%20solution%7D%7D)
Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L
![\text{Concentration of }[Fe(SCN)]^{2+}=\frac{1.08\times 10^{-5}mol}{0.025L}=4.32\times 10^{-4}M](https://tex.z-dn.net/?f=%5Ctext%7BConcentration%20of%20%7D%5BFe%28SCN%29%5D%5E%7B2%2B%7D%3D%5Cfrac%7B1.08%5Ctimes%2010%5E%7B-5%7Dmol%7D%7B0.025L%7D%3D4.32%5Ctimes%2010%5E%7B-4%7DM)
Thus, the concentration of is,
