The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.
<h3>Hooke's Law</h3>
Hooke's law states that the force applied to an elastic material is directly proportional to its extension, provided its elastic limit is not exceeded.
To calculate the amount of work done by Hooke's law, first, we need to find the force constant of the spring.
Formula:
- F = ke................. Equation 1
Where:
- F = Force applied
- k = Spring constant
- e = extension
make k the subject of the equation
- k = F/e................ Equation 2
From the question,
Given:
- F = 450 N
- e = 30 cm = 0.3 m
Substitute these values into equation 2
Finally, To find the work done in stretching the spring from 50 cm to 80 cm, we use the formula below.
- W = ke²/2........... Equation 3
Where:
- W = Work done
- k = spring constant
- e = extension
Also, From the question,
Given:
- e = (80-50) = 30 cm = 0.3 m
- k = 1500 N/m
Substitute these values into equation 3
- W = 1500(0.3²)/2
- W = 67.5 J.
Hence, The work done in stretching the spring from 50 cm to 80 cm is 67.5 J.
Learn more about Hooke's law here: brainly.com/question/12253978
What is the unit c denotes here
Answer:
orbitals
Explanation:
The region where an electron is most likely to be is called an orbital. Each orbital can have at most two electrons. Some orbitals, called S orbitals, are shaped like spheres, with the nucleus in the center.
The wave nature of light, due to the experiment having bright and dark bands corresponding to places where you have constructive and destructive interference.
