In order to answer these questions, we need to know the charges on
the electron and proton, and then we need to know the electron's mass.
I'm beginning to get the creepy feeling that, in return for the generous
5 points, you also want me to go and look these up so I can use them
in calculations ... go and collect my own straw to make the bricks with,
as it were.
Ok, Rameses:
Elementary charge . . . . . 1.6 x 10⁻¹⁹ coulomb
negative on the electron
plussitive on the proton
Electron rest-mass . . . . . 9.11 x 10⁻³¹ kg
a). The force between two charges is
F = (9 x 10⁹) Q₁ Q₂ / R²
= (9 x 10⁹ m/farad) (-1.6 x 10⁻¹⁹C) (1.6 x 10⁻¹⁹C) / (5.35 x 10⁻¹¹m)²
= ( -2.304 x 10⁻²⁸) / (5.35 x 10⁻¹¹)²
= 8.05 x 10⁻⁸ Newton .
b). Centripetal acceleration =
v² / r .
A = (2.03 x 10⁶)² / (5.35 x 10⁻¹¹)
= 7.7 x 10²² m/s² .
That's an enormous acceleration ... about 7.85 x 10²¹ G's !
More than enough to cause the poor electron to lose its lunch.
It would be so easy to check this work of mine ...
First I calculated the force, then I calculated the centripetal acceleration.
I didn't use either answer to find the other one, and I didn't use " F = MA "
either.
I could just take the ' F ' that I found, and the 'A' that I found, and the
electron mass that I looked up, and mash the numbers together to see
whether F = M A .
I'm going to leave that step for you. Good luck !
Answer:
Im not sure if im right but this is what i got( i have no clue how to explain im sorry)
1. False
2. False
3. True
4. False
a. Final pressure= 5atm
b. Work done = 5000 Joules
<h3>How to determine the parameters</h3>
Given;
- Temperature = 330K
- P1 = 6 atm
- V1 = 500cm^3
- V2 = 1500cm^2
In adiabatic expansion, temperature is constant
P1V1 = P2V2
Now, let's substitute the values into the formula
6 × 500 = 1500 P2
300 = 1500P2
Make 'p2' subject of formula
P2 = 1500/300
P2 = 5 atm
The formula for work done is given as:
Workndone = P ∆ volume
Work done = 5 × ( 1500 - 500)
Work done = 5 × 1000
Work done = 5000 Joules
Learn more about ideal gas law here:
brainly.com/question/25290815
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