Answer:
Mass by mass
Explanation:
Because it's telling only about mass in grams
The <u>Mole</u> is the SI unit that expresses the amount of substance.
Mole is defined as - The mole is the amount of substance containing the same number of entities as there are in the 12 grams of Carbon - 12.
Mole is denoted by using symbol mol.
Mole = 6.022 x 10²³ elementary entities.
These number of elementary entities in 1 mole is equal to or called as an Avogadro's number. Mole is equal to 6.022 x 10²³ because this number of entity is same as in exactly 12 g of carbon-12.
It is a very important SI unit of measured which is used by the chemists. Moles are used in measuring in small or tiny things such as atoms, molecules and the other tiny particles.
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The molecular formula :
C₆H₁₄O₃PF
<h3>Further explanation</h3>
Given
39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine.
Required
The molecular formula
Solution
mol ratio :
C = 39.1 : 12 = 3.258
H = 7.67 : 1 = 7.67
O = 26.11 : 16 = 1.632
P = 16.82 : 31 = 0.543
F = 10.3 : 19 = 0.542
Divide by 0.542
C = 6
H : 14
O = 3
P = 1
F = 1
The empirical formula :
C₆H₁₄O₃PF
(The empirical formula)n = the molecular formula
(C₆H₁₄O₃PF)=184.1
(6.12+14.1+3.16+31+19)n=184.1
(184)n=184.1
n = 1
The material needed to stop a beta particle is c. thin pieces of wood.
Metals like sodium, potassium, magnesium, etc. are extracted by electrolysis of their chlorides in molten state.
These metals are not extracted by reduction of their oxides with carbon because:
Carbon has less affinity for oxygen than these metals
Carbon is a weaker reducing agent than these metals
These metals easily form oxides with oxygen, their oxides are very stable. Affinity to the oxygen is one the greatest of all elements.
Reducing agent is element or compound who loose electrons in chemical reaction. Sodium, potassium, calcium and magnesium are very strong reducing agents because they easily loose one or two valence electrons.
Electrolysis is a chemical methode that uses electric currents for chemical reactions.
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