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mina [271]
3 years ago
9

What is the smallest halogen atom​

Chemistry
2 answers:
ad-work [718]3 years ago
4 0
The smallest halogen atom is fluorine
Marianna [84]3 years ago
4 0

Answer:

Hey mate...

Explanation:

This is ur answer.....

<em>This is because fluorine atoms are the smallest of the halogens—the atoms are bonded close together, which leads to repulsion between free electrons in the two fluorine atoms.</em>

Hope it helps you,

mark me as the brainliest....

Follow me! :)

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Sheena has a lump of sodium, a lump of potassium and a lump of lithium, but they’ve got mixed up and she doesn’t know which one
Arada [10]

Answer:

Explanation:

Just saw your request regarding answering this so here it is:

All of them belong of Group 1 in periodic table and thus are highly reactive! Pattern of reactivity for Group 1 (Alkali metals) increases as you move down the group as their radius keeps increasing and thus electrons can be easily lost. Thus, to ID the lumps, Sheena should look at their reactivity and she should get the following trend:

Most reactive: Potassium (K)

Intermediate: Sodium (Na)

Least reactive: Lithium (Li)

Hope it helps!

5 0
3 years ago
PLEASE HELP!!!!!
Free_Kalibri [48]
Umm I think it might be a b c in order?
4 0
3 years ago
WILL GIVE BRAINYEST! please help
RoseWind [281]
The answer is c i need brainlyest plz 
5 0
4 years ago
Given the following balanced equation, determine the rate of reaction with respect to [Cl2]. If the rate of Cl2 loss is 4.44 × 1
PolarNik [594]

Answer:

8.88 x 10⁻² M/s

Explanation:

The rate  of reaction for:

                    NO(g) + Cl₂ (g) ⇒  2NOCl(g)

is rate = -ΔNO/Δt = -ΔCl2/Δt = 1/2 ΔNOCl/Δt

so  ΔNOCl/Δt = 2 ΔCl2/Δt  = 2  x 4.44 × 10⁻²  M/s = 8.88 x 10⁻² M/s

In general given a reaction

                            aA + bB ⇒ cC + dD

rate = -1/a ΔA/Δt = -1/b ΔB/Δt = 1/c ΔC/Δt = 1/d ΔD/Δt

8 0
3 years ago
Suppose a 5.00 l sample of o2 at a given temperature and pressure contains 1.08
arsen [322]
Missing question: <span>A 5.00 L sample of O2 at a given temperature and pressure contains a 1.08x10^23 molecules. How many molecules would be contained in each of the following at the same temperature and pressure? </span>
a) 5.00 L H2.
<span>b) 5.00 L CO2.
Use </span>Avogadro's Law: The Volume Amount Law: <span>equal </span>volumes<span> of all gases, at the same temperature and pressure, have the same </span>number<span> of molecules. Because hydrogen and carbon(IV) oxide are gases, number of molecules are the same as number of oxygen molecules, so:
a) N(H</span>₂) = 1.08·10²³.
b) N(CO₂) = 1.08·10²³

5 0
3 years ago
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