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mylen [45]
3 years ago
6

Calculate the Force of Gravity acting on an object that has a mass of 1.3 kg. The object is on Earth so use 9.8m/s2 for the acce

leration due to gravity. 
A. 0.13 N
B. 7.5 N
C. 12.7 N
D. 1270 N
Physics
1 answer:
sweet-ann [11.9K]3 years ago
7 0
To calculate the gravitational force acting on an object given the mass and the acceleration due to gravity, use the following formula.

Fg = m • g
Fg = 1.3 kg • 9.8 m/s^2
Fg = 12.74 N or about 12.7 N.

The solution is C. 12.7 N.
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Name the physical quantity measured by the velocity-time graph?
VARVARA [1.3K]
The so-called "velocity-time" graph is actually a "speed-time" graph.  At any point
on it, the 'x'-coordinate is a time, and the 'y'-coordinate is the speed at that time.

'Velocity' is a speed AND a direction.  Without a direction, you do not have a velocity,
and these graphs never show the direction of the motion.  It seems to me that it would be
pretty tough to draw a graph that shows the direction of motion at every instant of time,
so my take is that you'll never see a true "velocity-time" graph. 

At best, it would need a second line on it, whose 'y'-coordinate referred to a second
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each instant. The graph of uniform circular motion, for example, would have a straight
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7 0
3 years ago
If a proton and an electron are released when they are 2.50×10^-10m apart (typical atomic distances), find the initial accelerat
katrin [286]

To solve this exercise, we will first proceed to calculate the electric force given by the charge between the proton and the electron (it). From the Force we will use Newton's second law that will allow us to find the acceleration of objects. The Coulomb force between two charges is given as

F = k \frac{q_1q_2}{r^2}

Here,

k = Coulomb's constant

q = Charge of proton and electron

r = Distance

Replacing we have that,

F = (9*10^9)(\frac{(1.602*10^{-19})^2}{2.5*10^{-10}})

F = 3.6956*10^{-9}N

The force between the electron and proton is calculated. From Newton's third law the force exerted by the electron on proton is same as the force exerted by the proton on electron.

The acceleration of the electron is given as

a_e = \frac{F}{m_e}

a_e = \frac{3.6956*10^{-9}}{9.11*10^{-31}}

a_e = 4.0566*10^{21}m/s^2

The acceleration of the proton is given as,

a_p = \frac{F}{m_p}

a_p = \frac{3.6956*10^{-9}}{1.672*10^{-27}}

a_p = 2.21*10^{18}m/s^2

3 0
2 years ago
A car increases velocity from 30 m/s to 60 m/s in 4 seconds. Calculate the average acceleration of the car over this time.
Lilit [14]

Answer:

B.7.5m/s2

Explanation:

average acceleration=change invelocity/time taken

a=(60-30)/4

=7.5m/s2

3 0
3 years ago
What is the most common state of matter in the universe
ch4aika [34]

Answer:

<u><em>Plasma</em></u>

Explanation:

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How does a steam engine do work?
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Steam enters a cylinder—- A
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