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storchak [24]
3 years ago
8

How high would you have to lift a 1000kg car to give it a potential energy of:

Physics
1 answer:
Elza [17]3 years ago
5 0

Given parameters:

Mass of the car = 1000kg

Unknown:

Height  = ?

To find the heights for the different amount potential energy given, we need to understand what potential energy is.

Potential energy is the energy at rest due to the position of a body.

 It is mathematically expressed as:

          P.E  = mgh

m is the mass

g is the acceleration due to gravity = 9.8m/s²

h is the height of the car

Now the unknown is h, height and we make it the subject of the expression to make for easy calculation.

               h = \frac{P.E }{mg}

<u>For 2.0 x 10³ J;</u>

                  h  = \frac{2000}{1000 x 9.8}   = 0.204m

<u>For 2.0 x 10⁵ J;</u>

                  h  = \frac{200000}{9.8 x 1000}   = 20.4m

<u>For 1.0kJ  = 1 x 10³J; </u>

                  h  = \frac{1000}{9.8 x 1000}   = 0.102m

   

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solmaris [256]

Answer:

f λ = c = 3.00E8      frequency * wavelength = speed of light

λ = c / f = 3.00E8 / 4.0E14 = 7.5E-7 m

Note 1 angstrom = 1.00E-10 m and 1 milli-micron = 1.00E-9 m

So the wavelength would be 7500 angstroms

The visible spectrum is 4000 A - 7000 A  or 400 - 700 milli-microns

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2 years ago
A group of interacting parts that move or work together
aliina [53]

Answer:

A system is a group of interrelated interacting, or interdependent parts that for a complex whole. A system is a group of interrelated interacting, or interdependent parts that for a complex whole.

Explanation: Hope this helps ;)

3 0
3 years ago
Cars with hybrid and electric motors what?
kogti [31]
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How long is the photons journey from the milky way to earth
fgiga [73]
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3 0
3 years ago
The inclined plane in the figure above has two sections of equal length and different roughness. The dashed line shows where sec
saveliy_v [14]

The static friction exerted on the block by the incline is \mu _ s _1 Mgcos \ \theta.

The given parameters;

  • <em>mass of the block, = M</em>
  • <em>coefficient of static friction in section 1, = </em>\mu_s_1<em />
  • <em>angle of inclination of the plane, = θ</em>

<em />

The normal force on the block is calculated as follows;

Fₙ = Mgcosθ

The static friction exerted on the block by the incline is calculated as follows;

F_s = \mu_s F_n\\\\F_s = \mu _s_1(Mg cos\ \theta)\\\\F_s = \mu _s_1 Mgcos\ \theta

Thus, the static friction exerted on the block by the incline is \mu _ s _1 Mgcos \ \theta

Learn more here:brainly.com/question/17237604

3 0
3 years ago
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