1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
storchak [24]
3 years ago
8

How high would you have to lift a 1000kg car to give it a potential energy of:

Physics
1 answer:
Elza [17]3 years ago
5 0

Given parameters:

Mass of the car = 1000kg

Unknown:

Height  = ?

To find the heights for the different amount potential energy given, we need to understand what potential energy is.

Potential energy is the energy at rest due to the position of a body.

 It is mathematically expressed as:

          P.E  = mgh

m is the mass

g is the acceleration due to gravity = 9.8m/s²

h is the height of the car

Now the unknown is h, height and we make it the subject of the expression to make for easy calculation.

               h = \frac{P.E }{mg}

<u>For 2.0 x 10³ J;</u>

                  h  = \frac{2000}{1000 x 9.8}   = 0.204m

<u>For 2.0 x 10⁵ J;</u>

                  h  = \frac{200000}{9.8 x 1000}   = 20.4m

<u>For 1.0kJ  = 1 x 10³J; </u>

                  h  = \frac{1000}{9.8 x 1000}   = 0.102m

   

You might be interested in
Two elevators begin descending from the same height. Elevator A has descended 4 feet after one second, 9 feet after two seconds,
solniwko [45]

Answer:

a) y = 400 ft  b) y = 350 ft

Explanation:

We can solve that problem with kinematic relationships

    y = v₀ t + ½ a t²

Let's apply this equation to the elevator 1

     y₁ = v₀ t₁ + ½ to t₁²

time t= 1 s

    y₁ = v₀ 1 + ½ a 1²

    y₁ = v₀ + ½ a

For t = 2s

    y₂ = v₀ 2 + ½ a 2²

    y₂ = 2 v₀ + 2 a

Let's write the equations and solve the system

    4 = v₀ + ½ a

    9 = 2 v₀ + 2 a

Let's multiply the first by -2

    -8 = -2v₀ -a

     9 = 2v₀ + 2 a

Let's add

      1 = a

We replace in the first

      4 = v₀ + ½ 1

      v₀ = 4- 1/2

      v₀ = 3.5

The equation for the first elevator is

      y = 3.5 t + ½  t²

For t = 10 s

      y = 3.5 10 + ½ 10²  

      y = 400 ft

We repeat the process for the second elevator

t = 1s

     y₁ = v₀ 1 + ½ a 1²

     3.5 = v₀ + ½ a

t = 2 s

     y₂ = v₀ 2 + ½ a 2²

     6.5 = 2 v₀ +2 a

multiply by -2

    -7 = -2 v₀ - a

     6.5 = 2 v₀ + 2 a

Let's add

    -0.5 = a

I replace in the first equation

    3.5 = v₀ + ½ (-0.5)

    v₀ = 3.5 + 0.25

    v₀ = 3.75

The equation is

    y = 3.75 t -0.25 t²

For t = 10s

    y = 3.75 10 - 0.25 10²

   y = 350 ft

8 0
3 years ago
Read 2 more answers
Ira is concerned about his posture. He tests it by seeing how long he can hold good posture and finds that he feels the most dis
larisa [96]

Answer: C

Explanation:

JUST TO SIMPLE

6 0
3 years ago
Question 1 of 25
Alekssandra [29.7K]

Answer:

(A)

Explanation:

5 0
3 years ago
Read 2 more answers
How long must a 0.70-mm-diameter aluminum wire be to have a 0.40 a current when connected to the terminals of a 1.5 v flashlight
Natalka [10]
By using Ohm's law, we can find what should be the resistance of the wire, R:
R= \frac{V}{I}= \frac{1.5 V}{0.40 A} =3.75 \Omega

Then, let's find the cross-sectional area of the wire. Its radius is half the diameter,
r=35 mm=0.35 \cdot 10^{-3} m
So the area is
A=\pi r^2 = \pi (0.35 \cdot 10^{-3} m)^2=3.85 \cdot 10^{-7} m^2

And by using the resistivity  of the Aluminum, \rho=2.65 \cdot 10^{-8} \Omega m, we can use the relationship between resistance R and resistivity:
R= \frac{\rho L}{A}
to find L, the length of the wire:
L= \frac{RA}{\rho}= \frac{(3.75 \Omega)(3,85 \cdot 10^{-7} m^2)}{2.65 \cdot 10^{-8} \Omega m}=54.48 m
4 0
3 years ago
Force due to gravity. While JWST is in orbit, the Earth will be at a distance of 1.494 x 109 m from the telescope, and the Sun w
Alona [7]

Answer:

the gravitational force JWST will feel from the Sun is 37.785 Newton { leftward }

Explanation:

Given that;

distance of earth from the telescope r1 = 1.494 × 10⁹ m

and the Sun will be 1.49598 × 10¹¹ m further away

so r2 = r1 + 1.49598 × 10¹¹

r2 = 1.494 × 10⁹ m + 1.49598 × 10¹¹ m = 1.51092 × 10¹¹ m

mass of sun Ms = 1.9884 × 10³⁰ kg

mass of earth Me = 5.945× 10²⁴ kg

mass of JWST Mj = 6500 kg

What is the gravitational force JWST will feel from the Sun (strength and direction)?

the gravitational force of the sun will be attractive based on Newton law of gravitational force; so

Fjs = GMjMs / r2²

constant G = 6.674 × 10⁻¹¹ Nm²/kg²

Force on the JWST by the sun will be;

Fjs = GMjMs / r2² { leftward}

we substitute

Fjs = [(6.674 × 10⁻¹¹ Nm²/kg²)(6500 kg )(1.9884 × 10³⁰ kg)] / (1.51092 × 10¹¹ m)²

=  (8.62587804 × 10²³) / ( 2.28287925 × 10²² )

= 37.785 Newton { leftward }

Therefore, the gravitational force JWST will feel from the Sun is 37.785 Newton { leftward }

7 0
3 years ago
Other questions:
  • A magnetic field of 0.080 T is in the y-direction. The velocity of wire segment S has a magnitude of 78 m/s and components of 18
    14·1 answer
  • How are airplanes artificially pressurized?
    8·1 answer
  • Kalyan ramji sain, of india, had a mustache that measured 3.39 m from end to end in 1993. suppose two charges, q and 3q, are pla
    12·1 answer
  • Structures that trap light energy and perform photosynthesis
    13·1 answer
  • If the mass of the Moon were suddenly to double, and the distance to the moon cut in half, how would the gravitational force bet
    14·2 answers
  • a dog runs after the car, the car is travelling at an average speed of 5 m/s, the dog runs 20 m in 5s. does she catch the car
    12·1 answer
  • Which imaging technique uses X-rays to make cross-sectional images of the body?
    11·2 answers
  • A kayak took 5 hours to finish its trip on a river. If it traveled at an
    6·1 answer
  • Is it possible for an object to change its weight without changing its mass? Explain why or why not
    13·1 answer
  • An object weighing 2.7n while in air and 1.2n when completely immersed in water.find the relative density of the object
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!