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iragen [17]
3 years ago
9

Which contribution added to Rutherford's discovery of a positive nucleus?

Chemistry
1 answer:
posledela3 years ago
7 0

Answer:

A: Electrons are scattered in an atom.

Explanation:

Ernest Rutherford performed the gold foil experiment which gave a deeper perspective into what an atom really is. In his experiment, he bombarded a thin gold foil with an alpha particle source.

From the behavior of the alpha particles that associated with the gold foil, a number of conclusions were drawn:

  1. He suggested that an atom has a small positively charged nucleus where the bulk of the atomic mass is concentrated.
  2. Surrounding the nucleus is a large space which contains the electrons.
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How many atoms of oxygen are in 0.100 mol of silicon dioxide?
lys-0071 [83]
1) Silicon dioxide formula: SiO2  ....... 2 is a subscript for the O atom

2) From the formula you have 1 molecula of SiO2 contains 1 atom of SiO2

3) Then, 0.100 mol of SiO2 contains 0.1 mol of Si

4) Multiply by Avogadro's number: 0.100mol *  6.022*10^23 atoms/mol= 6.02*10^22 atoms

Answer: 6.02*10^22 atoms
3 0
3 years ago
Convert 16.8 L of nitrogen monoxide gas at STP to grams .
german

Answer:

See explanation

Explanation:

1 mole of a gas occupies 22.4 L

x moles occupies 16.8 L

x = 1 mole *  16.8 L/22.4 L

x = 0.75 moles

number of moles = mass/molar mass

mass =  number of moles  * molar mass

mass =  0.75 moles * 30.01 g/mol = 22.5075 g = 2.25 * 10^1 g

the coefficient of the scientific notation answer = 2.25

the exponent of the scientific notation answer = 1

significant figures are there in the answer = 6

the right most significant figure in the answer = 3

2.

number of moles = 12.5g/38g/mol = 0.3289 moles

1 mole occupies 22.4 L

0.3289 moles occupies 0.3289 moles * 22.4 L/1 mole

= 7.36736 L = 7.36736 * 10^0 L= 7.37 * 10^0 L

the coefficient of the scientific notation answer =7.37

the exponent of the scientific notation answer = 0

significant figures are there in the answer = 6

the right most significant figure in the answer= 3

8 0
3 years ago
Plssssssssssssssssssmejepleplele
Leona [35]

Answer:

Yes the two of the answer is True

3 0
3 years ago
Read 2 more answers
A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specif
slavikrds [6]

Answer:

0.0702J/g°C the specific heat capacity of the metal.

Explanation:m

Q=m\times c\times \Delta T=m\times c\times (T_{2}-T_{1})

where,

Q = heat absorbed by metal = 186.75 J

m_1 = Mass of metal= 19 g

T_1 = Initial  temperature of metal = 35^oC

T_2 =Final  temperature of metal = 175^oC

c = specific heat of metal= ?

186.75 J=19 g\times c\times (175^oC-35^oC)

c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}

c=0.0702J/g^oC

0.0702J/g°C the specific heat capacity of the metal.

6 0
3 years ago
An object weighting 9.6 grams is placed in a graduated cylinder displacing the volume from 10.0mL to 13.2 mL
grigory [225]

The volume of object is 3.2 ml

<h3>Explanation:</h3>

Given:

Mass of the object = M = 9.6 g

Initial volume of liquid: V_1 = 10.0\ ml

Final volume of liquid after displacement: V_2 = 13.2\ ml

Total volume of the displaced object inside a graduating cylinder will be given as difference between the final volume and initial volume of the expanding object.

V = V_2-V_1 = 13.2 -1 0.0 = 3.2\ ml

V = 3.2 ml

3 0
3 years ago
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