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Roman55 [17]
3 years ago
11

MIDTERM

Physics
1 answer:
egoroff_w [7]3 years ago
3 0
Loop law for v1, r1, r2, r3
lv1 = current from v1
Ir3 = current pass r3
- v1 + Iv1(r1) + Iv1(r2) + Ir3(r3) = 0
-5 + Iv1(200) + Iv1(200) + Ir3(100) = 0
400Iv1 = 5 - 100Ir3 ...(1)

current law at B
Iv1 + I1 - Ir3 - I2 = 0
Iv1 + 0.001 - Ir3 - 0.005 = 0
Iv1 = Ir3 + 0.004 ...(2)

solve by using (1),(2)
Ir3=0.0068A, Iv1=0.108A

Vb = Ir3(r3) = 0.0068(100) = 0.68V

Va = Vb + Iv1(r2) = 0.68 + 0.0108(200) = 0.68 + 2.16 = 2.84V

power = I^2(r)
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