Answer:
true
Explanation:
dbgkdodocofkci ifkdcl k kfododocp v
Answer:
1) F = 24 N
2) Distance = 1 m
Explanation:
We are given;
Mass; m = 120 g = 0.12 kg
Initial velocity; u = 20 m/s
Final velocity; v = 0 m/s since it came to rest.
Time; t = 0.1 s
We can calculate acceleration from Newton's first equation of motion;
a = (v - u)/t
a = (0 - 20)/0.1
a = -200 m/s²
1) magnitude of the resistance will be;
F = ma
F = 0.12 × (-200)
F = -24 N
Since, we are dealing with the magnitude, we will take the absolute value. Thus, F = 24 N
2) To find the distance moved by the bullet, we know that;
Distance = Average speed × time
Thus;
Distance = ((v + u)/2) × t
Distance = ((0 + 20)/2) × 0.1
Distance = 1 m
(a) The height of the cliff will be 8.26 meters.
(b) The time would it take to reach the ground will be 0.717 sec.
<h3>What is velocity?</h3><h3 />
The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity. it is a time-based component.
(a) The height of the cliff will be 8.26 meters.
According to Newton's second equation of motion
Hence The height of the cliff will be 8.26 meters.
(b)The time would it take to reach the ground will be 0.717 sec.
We must have the final velocity to find the time so;
According to Newton's third equation of motion ;
Hence the time would it take to reach the ground will be 0.717 sec.
To learn more about the velocity refer to the link ;
brainly.com/question/862972
Answer:
The answer is "The object's speed relative to S can be greater than or less than its speed relative to S', depending on the actual values."
Explanation:
The S' frame and the object are moving in a positive direction. The object is moving with respect to the S frame so the S frame the rest frame
take the velocity of the object with respect to the rest frame as v and the velocity of the S' frame with respect S frame as v2
relative velocity of the object to the S' frame would be
Vrel = v2- v
This means the Vrel of the object with respect to the S' frame is less than the Vrel of the object with respect to the S frame
However is the S' velocity is greater than that of the object then the Vrel of the object with respect to the S' frame is greater than the Vrel of the object with respect to the S frame.
This would mean the second option is the answer, the relative speed of the object depends on the actual values.
I’m not going to church tomorrow or Friday I don’t want to go go back up
