Answer and explanation:
A correct option is an option (B).
The electrical force between two charges is given as,
The electrical force is directly proportional to the product of two charges. Thus Force will depend on two charges irrespective of their signs.
Option (A) is incorrect because if charges are opposite, the value of force will not be zero. It will be -ve.
Option (C) is incorrect because the force is directly proportional to the product of charges, it depends on the amount of charge.
Option (D) is also incorrect because the force in inversly proportional to the distance between two charges. Thus, if the distance between two charges is increased, the force between two charges will decrease.
Concllusion:
The correct option is option (B).
Answer:6m/s^2
Explanation:
Mass =3kg
Force=18N
Acceleration =force ➗ mass
Acceleration =18 ➗ 3
Acceleration =6
Acceleration =6m/s^2
The upper temperature range for stars is : c. 40,000 K
Every object has their own upper and lower temperature
This indicate the maximum possible energy that a star could release to its surrounding if its somehow exploded.
Note that the electric field lines begin from the higher voltage to the lower
Because the negative pole is lower voltage than the positive pole
The lines go out the positive charges and go in the negative charges
Then, the correct statement is:
<u>C. Source A is negatively charged and source B is positively charged.</u>
Answer:
Explanation:
Given that,
We have two capacitors connected in series
C1=2.0-μF
C2=4.0-μF
Then the equivalent of their series connection
1/Ceq = ½ + ¼
1/Ceq= (2+1)/4
1/Ceq=¾
Taking the reciprocal
Ceq= 4/3 μF
The capacitors are connected to a battery of 1kv
V=1000Volts
We know that,
Q=CV
Where Q is charge
C is capacitance and
V is voltage
Then, Q=4/3 ×1000
Q=4000/3 -μC
Since the capacitors are in series, then the charge pass through them, so each charge on the capacitors are 4000/3 μF
After the capacitor has been charge, the capacitor are disconnect and reconnected in parallel to each other,
For parallel connection, they have the same voltage but different charges.
When connected in parallel, there is a charge redistribution,
And the total charge will be 2•4000/3=8000/3 -μF
Then, Q1 +Q2= 8000/3 μF
Now the charge on each capacitor will be, let them have a common voltage V
Q=CV
Then, Q1=C1V
Q1= 2×V=2V
Q2= 4×V=4V
Then, Q1+Q2=8000/3
4V+2V=8000/3
6V=8000/3
V=8000/(3×6)
V=4000/9
V=444.44Volts
Now, Q1=2V
Q1=2×4000/9
Q1=8000/9 μF
Also, Q2=4V
Q2=4×4000/9
Q2=16000/9 μF
