Answer:
Density of copper = 8.9 g/cm³
The density of liquid mercury is 13.6 g/cm³ which means mercury is denser than copper so copper will float on liquid mercury.
Explanation:
Given data:
weight of copper metal = 1896 g
Dimensions of block = 8.4 cm, 5.5 cm, 4.6 cm
Density of copper = ?
Will it float to the liquid mercury = ?
Solution:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
volume of coper metal = 8.4 cm × 5.5 cm × 4.6 cm
volume of coper metal =212.52 cm³
d = 1896 g/ 212.52 cm³
d = 8.9 g/cm³
The density of liquid mercury is 13.6 g/cm³ which means mercury is denser than copper so copper will float on liquid mercury.
Answer:
92.75%
Explanation:
The overall chemical equation for the reaction in the preparation of alum from the aluminium can be expressed as:
From above; we will see that 2 moles of Aluminium react with sulphuric acid and water to produce 2 moles o aluminium alum.
Therefore, the theoretical yield can be determined as:
= 4.789g of 
To find the percent yield, we need to divide the actual yield by the theoretical yield and then multiply it with 100.
∴
percent yield = ( mass of alum(g)/theoretical yield(g) ) × 100
percent yield = ( 4.789g / 5.1629g ) × 100%
percent yield = 0.9275 × 100%
percent yield = 92.75%
Thus, the percent yield of the experiment 92.75%
<span>The number of valence electrons from the electron configuration,write 1s², 2s² 2p⁶, 3s² 3p⁴.
The "big" numbers are the principal quantum numbers (n) which correspond to the major energy levels, and sub-scripted numbers are the number of electrons in the sub-energy level.
</span><span>For sulfur, the highest principal quantum number is 3, and there are 6 electrons in the 3s² and 3p⁴ sublevels. </span>
Answer:
V = 18,493.5114 cm³
Explanation:
Dimensions are;
L = 35 inches
W = 35 cm
H = 0.065 yards
Now, volume is given by;
V = LWH
But our dimensions need to all be in the same unit, so let's convert to cm.
L = 35 inches = 35 × 2.54 cm = 88.9 cm
H = 0.065 yards = 0.065 × 91.44 = 5.9436 cm
Thus;
V = 88.9 × 35 × 5.9436
V = 18,493.5114 cm³
The circumstance which is it appropriate to ignore a data point when drawing the best line through data to make a graph is when there is the presence of the outliers.
<h3>What is a Graph?</h3>
This is defined as the pictorial representation of data or variables in an organized manner.
The graph when plotted contain a lot of points in which a line is drawn to pass the majority of them. In situations whereby some of the data point don't follow the line drawn then it must be ignored.
This is because they don't usually reflect the trend of the data which is why this particular scenario was chosen as the most appropriate choice.
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