Answer:
0.21 g
Explanation:
The equation of the reaction is;
NaCl(aq) + AgNO3(aq) -----> NaNO3(aq) + AgCl(s)
Number of moles of NaCl= 0.0860 g /58.5 g/mol = 0.00147 moles
Number of moles of AgNO3 = 30/1000 L × 0.050 M = 0.0015 moles
Since the reaction is 1:1, NaCl is the limiting reactant.
1 mole of NaCl yields 1 mole of AgCl
0.00147 moles of NaCl yields 0.00147 moles of AgCl
Mass of precipitate formed = 0.00147 moles of AgCl × 143.32 g/mol
= 0.21 g
Greetings!
Significant Digits are:
-Non Zero Numbers
-Zeros in between Non Zero Numbers
-Trailing zeros to the right of the decimal point
So when rounding to 4 significant figures, we get:
1023
Hope this helps.
-Benjamin
Answer:
Explanation:
1 mole of methane = C + H4 = 12 + 4 = 16
32 grams of methane is 32/16 = 2 moles.
1 moles of methane contains 4 moles of hydrogen (CH4). Note the 4 in CH4
2 moles of methane = 8 moles of hydrogen.
H2O has 2 moles of hydrogen
Each mole of water contains 2 moles of hydrogen.
8 moles of hydrogen / 2 moles = 4 moles of water.
The answer is D hope this helps
Answer:
0.00840
Explanation:
The computation of the mole fraction is as follow:
As we know that
Molar mass = Number of grams ÷ number of moles
Or
number of moles = Number of grams ÷ molar mass
Given that
Number of moles of CaI2 = 0.400
And, Molar mass of water = 18.0 g/mol
Now Number of moles of water is
= 850.0 g ÷ 18.0 g/mol
= 47.22 mol
And, Total number of moles is
= 0.400 + 47.22
= 47.62
So, Molar fraction of CaI2 is
= 0.400 ÷ 47.62
= 0.00840
