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2 years ago

6

4 A Small rock

1 answer:

vodomira [7]2 years ago

6 0

3 millimeters is the rock

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Why is water less dense as a solid than a liquid? In ecological terms, why is this of particular importance?

Georgia [21]

<span>Persamaan setara pada reaksi besi dengan asam klorida membentuk besi (II) klorida dan gas hidrogen </span>

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2 years ago

To separate a mixture of iron filings and salt, the<br> most efficient method would be

CaHeK987 [17]

Iron filings can be attracted by the magnet whereas salt can not. So the mixture can be separated by a magnet

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3 years ago

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However, when the temperature increases, the solubility of gaseous solutes will _______?

babunello [35]

Answer:

Decrease

Explanation:

Since the speed in which the gas molecules are faster as they are heated, they fly around in the container and logically, it is harder to insert a moving object into water than something more stationary or slower.

7 0

2 years ago

What is the molar concentration of hydronium ions in a sample of a soft drink that has a ph of 4?

hammer [34]

[ $H^{+}$ ] value of soft drink is 0.0001mol/l when given pH is 4.

Given:

pH = 4

Needs to find: [ $H^{+}$ ]

Formula to find: pH=−log $_{10}$ [ $H^{+}$ ]

We can put the values of pH in above formula as,

pH=−log $_{10}$ [ $H^{+}$ ]

4 =−log $_{10}$ [ $H^{+}$ ]

To calculate hydonium ion concentration, formula is as follows;

[ $H^{+}$ ] = $10^{-pH}$

[ $H^{+}$ ] = $10^{-4}$ = 0.0001mol/l

[ $H^{+}$ ] value of soft drink is 0.0001mol/l

Learn more about pH here:

brainly.com/question/2288405

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6 0

1 year ago

Calcium hydroxide is a strong base but is not very soluble ( Ksp = 5.02 X 10-6 ). What is the pH of a saturated solution of Ca(O

Misha Larkins [42]

Answer : The pH of a saturated solution is, 12.33

Explanation : Given,

$K_{sp}$ = $5.02\times 10^{-6}$

First we have to calculate the solubility of $OH^-$ ion.

The balanced equilibrium reaction will be:

$Ca(OH)_2\rightleftharpoons Ca^{2+}+2OH^-$

Let the solubility will be, 's'.

The concentration of $Ca^{2+}$ ion = s

The concentration of $OH^-$ ion = 2s

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ca^{2+}][OH^-]^2$

Let the solubility will be, 's'

$K_{sp}=(s)\times (2s)^2$

$K_{sp}=(4s)^3$

Now put the value of $K_[sp}$ in this expression, we get the solubility.

$5.02\times 10^{-6}=(4s)^3$

$s=1.079\times 10^{-2}M$

The concentration of $Ca^{2+}$ ion = s = $1.079\times 10^{-2}M$

The concentration of $OH^-$ ion = 2s = $2\times (1.079\times 10^{-2}M)=2.158\times 10^{-2}M$

First we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (2.158\times 10^{-2})$

$pOH=1.67$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-1.67=12.33$

Therefore, the pH of a saturated solution is, 12.33

7 0

2 years ago