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3 years ago

Quantum transitions that result in the characteristic sharp lines of the X-ray spectrum always involve

Chemistry

1 answer:

labwork [276]3 years ago

4 0

Answer: 5

Explanation: this is because the energy level of the emitted of absorbed photon increases as the number of electron shell decreases, thereby making the inner shell have higher energy than other shells

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Choose the correct statement. The cathode is the electrode where the oxidation takes place. Both oxidation and reduction may tak

gregori [183]

Answer:

The cathode is the electrode where the reduction takes place.

Explanation:

Cell has three components:

an electrolyte and two electrodes which is a cathode and an anode.

Electrolyte is usually solution of the water or other solvents in which the ions are dissolved.

In electrolytic cell:

Negatively charged electrode is the cathode where the process of reduction takes place.

Positively charged electrode is the anode where the process of oxidation takes place.

In galvanic cell:

Positively charged electrode is the cathode where the process of reduction takes place.

Negatively charged electrode is the anode where the process of oxidation takes place.

So, the correct answer is - The cathode is the electrode where the reduction takes place.

6 0

3 years ago

Answer truthfully:))

Elina [12.6K]

Answer:

Formula: $Velocity \: V = f \lambda \\ Solution: = 5 \times 0.8 \\ = 4 \: {ms}^{ - 1}$

3 0

3 years ago

Read 2 more answers

A 80.0 g piece of metal at 88.0°C is placed in 125 g of water at 20.0°C contained in a calorimeter. The metal and water come to

grandymaker [24]

Answer:

The specific heat of the metal is 0.485 J/g°C

Explanation:

Step 1: Data given

Mass of the piece of metal = 80.0 grams

Mass of the water = 125 grams

Initial temperature of the metal = 88.0 °C

Initial temperature of water =20.0 °C

Final temperature = 24.7 °C

pecific heat of water is 4.18 J/g*°C

Step 2: Calculate specific heat of the metal

Qgained = -Qlost

Q =m*c*ΔT

Qwater = - Qmetal

m(water)*c(water)*ΔT(water) = -m(metal)*c(metal)*ΔT(metal)

with mass of water = 125 grams

with c( water) = 4.18 J/g°C

with ΔT(water) = T2-T1 = 24.7 - 20 = 4.7°C

with mass of metal = 80.0 grams

with c(metal) = TO BE DETERMINED

with ΔT(metal) = 24.7 - 88.0 = -63.3 °C

125*4.18*4.7 = -80 * C(metal) * -63.3

2455.75 = -80 * C(metal) * -63.3

C(metal) = 2455.75 / (-80*-63.3)

C(metal) = 0.485 J/g°C

The specific heat of the metal is 0.485 J/g°C

3 0

3 years ago

Benzene would react_____________.

Vlada [557]

Answer: Benzene is less reactive than methylbenzoate and more reactive than Nitrobenzene

Explanation:

This is because the methyl group on the benzene ring is an electron donating group leading to the activation of the ring and subsequently leading to more canonical resonance structure at the intermediate stage of the reaction enhancing the faster reactivity

However for the Nitrobenzene the nitro group is an electron withdrawing group leading to a slower activation and less resonance canonical structure at the reaction intermediate leading to a slower reaction than the reaction of benzene without the nitro group

4 0

4 years ago

What changes occur in O + O = O2

ozzi

Answer:

They went from atoms to oxygen molecule.

Explanation:

I'm not sure if this is the answer your teacher is looking for, but in simple terms you had 2 oxygen atoms. Together they make an oxygen molecule, which is the stuff we breathe.

5 0

3 years ago