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3 years ago

10. Which of state of matter has no definite shape but does have a definite volume?

Chemistry

1 answer:

il63 [147K]3 years ago

4 0

Answer:

Gas, has no shape but does take up volume

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guys please help me WILL MARK BARINLIEST If you have 5.7 x 10^24 molecules of O2 at STP, how many liters of O2 do you have? must

zmey [24]

Answer:

212.8 dm^3 or L

Explanation:

1 mole of any sub=6.02×10^23 molecules

X mole of O2=5.7×10^24 molecules

X mole=5.7×10^24/6.02×10^23

=9.5 mole

1 mole of any gas at stp=22.4 dm^3

Therefore, 9.5 mole of O2 will be 22.4×9.5

=212.8 dm^3

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Which is a living part of an ecosystem? A.soil B.bacteria C.animal bones D.minerals

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3 years ago

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The solubility of a gas is 0.890 g/L at a pressure of 120 kPa. What is the solubility of the gas if the pressure is changed to 1

IgorC [24]

The solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

<h3>Effect of Pressure on Solubility </h3>

As the pressure of a gas increases, the solubility increases, and as the pressure of a gas decreases, the solubility decreases.

Thus, Solubility varies directly with Pressure

If S represents Solubility and P represents Pressure,

Then we can write that

S ∝ P

Introducing proportionality constant, k

S = kP

S/P = k

∴ We can write that

$\frac{S_{1} }{P_{1} } = \frac{S_{2} }{P_{2} }$

Where $S_{1}$ is the initial solubility

$P_{1}$ is the initial pressure

$S_{2}$ is the final solubility

$P_{2}$ is the final pressure

From the given information

$S_{1} = 0.890 \ g/L$

$P_{1} = 120 \ kPa$

$P_{2} = 100 \ kPa$

Putting the parameters into the formula, we get

$\frac{0.890}{120}=\frac{S_{2}}{100}$

$S_{2}= \frac{0.890 \times 100}{120}$

$S_{2}= 0.742 \ g/L$

Hence, the solubility of the gas if the pressure is changed to 100 kPa is 0.742 g/L

Learn more on Solubility here: brainly.com/question/4529762

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1 year ago