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kenny6666 [7]
3 years ago
8

Elton's mother has been nagging and nagging that he should stop fooling around with his guitar and start studying. Finally, in o

rder to stop her nagging, Elton complies and hits the books. This example illustrates the effect of ________.
a. positive reinforcement

b. negative reinforcement

c. positive punishment

d. negative punishment

Elton's mother has been nagging and nagging that he should stop fooling around with his guitar and start studying. Finally, in order to stop her nagging, Elton complies and hits the books. This example illustrates the effect of ________.



a. positive reinforcement

b. negative reinforcement

c. positive punishment

d. negative punishment
Physics
1 answer:
horrorfan [7]3 years ago
7 0
The correct answer is b. negative reinforcement. Since Elton followed his mother to stop her from nagging, it is called negative reinforcement. Had she used other ways to persuade him to study, it would be a positive reinforcement. Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help. 
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An ideal parallel plate capacitor with a cross-sectional area of 0.4 cm2 contains a dielectric with a dielectric constant of 4 a
Mrrafil [7]

Answer: 283.2\times 10^{-9}\ nC

Explanation:

Given

Cross-sectional area A=0.4\ cm^2

Dielectric constant k=4

Dielectric strength E=2\times 10^8\ V/m

Distance between capacitors d=5\ mm

Maximum charge that can be stored before dielectric breakdown is given by

\Rightarrow Q=CV\\\\\Rightarrow Q=\dfrac{k\epsilon_oA}{d}\cdot (Ed)\quad\quad [V=E\cdot d]\\\\\Rightarrow Q=k\epsilon_oAE\\\\\Rightarrow Q=4\times 8.85\times 10^{-12}\times 0.4\times 10^{-4}\times 2\times 10^8\\\\\Rightarrow Q=28.32\times 10^{-8}\\\\\Rightarrow Q=283.2\times 10^{-9}\ nC

4 0
3 years ago
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A stone is thrown vertically upward with a speed of 18.0 m/s. How fast is it moving when it reaches a height of 11.0m? How long
steposvetlana [31]
Given: v0= 18.0 m/s, y0=0m, yf=11m, g=-9.81 m/s^2 

v0= initial velocity, vf= final velocity, y0= initial height, yf= final height, g= gravity, sqrt()= square root, ^2=squared 

vf^2=v0^2 + (2)(g)(yf-y0) 
vf^2=(18.0 m/s)^2+(2)(-9.81 m/s^2)(11 m-0m) 
vf^2=18.0 m/s)^2 + (-19.62 m/s^2)(11 m)
vf^2=(324 m^2/s^2) - (215.82 m^2/s^2) 
vf^2=108.18 m^2/s^2 
vf=sqrt(108.18 m^2/s^2) 
vf=10.4 m/s
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If a rock is thrown upward on the planet Mars with a velocity of 10 ms, its height in meters seconds later is given by (a) Find
Delicious77 [7]

Answer:

1) X(t)=Xo+So(t)+\frac{1}{2} g(t)^{2}

2) S(Δt)=So+g(Δt)

Explanation:

I think the equation they gave you for the Height upon time in seconds it's (1), where if you see, you will find the gravity, that you should multiply by 2 because, its divided by two in (1) (that should be your (a)), then, once you find your gravity, you can use the equation (2) to know the Final Speed replacing g , at the time asked, remember that g is gravity, and Δt is the: final time- initial time.

so in the [1,2] interval of time, your Δt=1s, and in [1,1.5] is Δt=0,5s.

i hoped it helped you even though i cant give you the exact answer right now.

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