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SVEN [57.7K]
3 years ago
12

A circuit has a current of 2 A. If the resistance in the circuit decreases to one-fourth of its original amount while the voltag

e
emains constant, what will be the resulting current?
0.5 A
2A
4A
BA
Physics
1 answer:
klasskru [66]3 years ago
8 0

Answer:

two ampheres

Explanation:

the formula for calculating voltage is V=IR so if the current which is I is 2 and the resistance which is R is decreased to one forth then we will say

R=x multiplied by 1/4=x/4

V=2x/4 cross multiply then we have

since the voltage is constant then it is=1

so 4=2x divide both sides by 2 we then get 2 as our answer

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To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi
maria [59]

Answer:

a) a = 5.03x10¹³ m/s²

b) V_{f} = 4.4 \cdot 10^{5} m/s

Explanation:    

a) The acceleration of the positron can be found as follows:

F = q*E    (1)

Also,

F = ma    (2)

By entering equation (1) into (2), we have:

a = \frac{F}{m} = \frac{qE}{m}

<u>Where:</u>

F: is the electric force

m: is the particle's mass = 9.1x10⁻³¹ kg

q: is the charge of the positron = 1.6x10⁻¹⁹ C    

E: is the electric field = 286 N/C

a = \frac{qE}{m} = \frac{1.6 \cdot 10^{-19} C*286 N/C}{9.1 \cdot 10^{-31} kg} = 5.03 \cdot 10^{13} m/s^{2}

b) The positron's speed can be calculated using the following equation:

V_{f} = V_{0} + at

<u>Where</u>:

V_{f}: is the final speed =?

V_{0}: is the initial speed =0

t: is the time = 8.70x10⁻⁹ s

V_{f} = V_{0} + at = 0 + 5.03 \cdot 10^{13} m/s^{2}*8.70 \cdot 10^{-9} s = 4.4 \cdot 10^{5} m/s

I hope it helps you!

4 0
3 years ago
Carl went on a Euro Trip and was traveling from Spain to Russia. When he looked on the map it said Russia was 7035 km away from
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Answer:

The average speed would be 279.167 meters per second.

Explanation:

Speed ​​is the magnitude that expresses the variation in position of an object and as a function of time. In other words, speed is defined as the relationship established between the distance traveled and the time elapsed in the movement of a mobile.

Speed can be calculated using the following expression:

Speed=\frac{distance}{time}

In this case:

  • distance= 7,035 km
  • time= 7 hours

Since the required unit of speed is meter per second, then you convert from km to meters for the case of distance, and from hours to seconds for the case of time. So:

  • distance= 7,035 km= 7,035,000 m (being 1 km= 1,000 m)
  • time= 7 hours= 420 minutes= 25,200 seconds (being 1 hour=60 minutes and 1 minute=60 seconds)

Replacing in the definition of speed:

Speed=\frac{7,035,000 meters}{25,200 seconds}

Solving:

Speed=279.167\frac{meters}{ seconds}

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