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Bogdan [553]
4 years ago
7

Why does the energy of a sound wave decrease over time

Physics
1 answer:
Svet_ta [14]4 years ago
6 0
Sound is a longitudinal wave that carries energy. Sound needs a medium to propagate through (this means that sound cannot propagate in vacuum).

The medium usually determines the speed of the wave travelling through it.

As the sound waves travel in a medium, this medium begins to decrease, therefore, the energy of the sound also decreases.

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Complete the statement below.
nikklg [1K]

Answer:

Explanation:

Hydrogen and hydroxide ions reacts to form water in a neutralisation reaction

3 0
4 years ago
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A locomotive is pulling 15 freight cars, each of which is loaded with the same amount of weight. The mass of each freight car (w
VMariaS [17]

Answer:

298,220 N

Explanation:

Let the force on car three is T_23-T_34

Since net force= ma

from newton's second law we have

T_23-T_34 = ma

therefore,

T_23-T_34 = 37000×0.62

T_23= 22940+T_34

now, we need to calculate

T_34

Notice that T_34 is accelerating all 12 cars behind 3rd car by at a rate of 0.62 m/s^2

F= ma

So, F= 12×37000×0.62= 22940×12= 275280 N

T_23 =22940+T_34= 22940+ 275280= 298,220 N

therefore, the tension in the coupling between the second and third cars

= 298,220 N

3 0
3 years ago
A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average forc
Natali5045456 [20]

Answer:

<h2>9.3kN</h2>

Explanation:

Step one:

given data

mass of bullet= 0.02kg

speed v=700m/s

time taken =1.5ms= 0.0015 seconds

Step two:

we know that from the first law

F=ma-----1  first law of motion

also, we know that

a=v/t----2

put a=v/t in equation 1 we have

F=mv/t

Step three:

substitute our given data to find force

F=0.02*700/0.0015

F=14/0.0015

F=9333.33N

F=9.3kN

<u>The average force exerted is 9.3kN</u>

7 0
3 years ago
Two identical parallel plate capacitors A and B connected to a battery of V volts w/ the switch S closed. The switch is now open
Basile [38]
The electrostatic energy stored in a capacitor with capacitance C_0, with a voltage difference V applied to it, and without dielectric, is given by
U_0 =  \frac{1}{2} C_0 V^2
Now let's assume we fill the space between the two plates of the capacitor with a dielectric with constant k. The new capacitance of the capacitor is
C_k = k C_0
So, the energy stored now is
U_k =  \frac{1}{2}C_k V^2= \frac{1}{2}kC_0 V^2

Therefore, the ratio between the energies stored in the capacitor before and after the introduction of the dielectric is
\frac{U_k}{U_0}= \frac{ \frac{1}{2}kC_0 V^2 }{ \frac{1}{2} C_0 V^2}=  k
5 0
3 years ago
Como foi a despedida do bilhete?​
Dmitrij [34]
Can you translate to english ?
8 0
3 years ago
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