Answer:
(<em>i) Concentrated HNO3 can be stored and transported in aluminium containers as it reacts with aluminium to form a thin protective oxide layer on the aluminium surface. This oxide layer renders aluminium passive. (ii) Sodium hydroxide and aluminium react to form sodium tetrahydroxoaluminate(III) and hydrogen gas.</em>
Here is some different pics of a water table. I hope this is what you are looking for :). You can click the pictures to in large them.
248.72 g/mol
CuSO4 has a molar mass of 159.62. H2O has a molar mass of 18.02, which is multiplied by 5 to reflect the 5 H2O molecules.
159.62+5(18.02)=249.72 g/mol
Answer:
mCO2= 49.6932 kgCO2
Explanation:
Hello! Let's solve this!
First we propose the balanced equation C3H8 + 5O2 ---> 3CO2 + 4H2O
We see that each mole of C3H8 (propane) we get 3 moles of CO2
From the propane volume we can obtain the grams of propane used.
molpropane = 26.5L * (1000mL / 1L) * (0.621g / 1mL) * (1mol / 44g) = 374.01mol propane
mCO2 = 374.01molC3H8 * (3molCO2 / 1molC3H8) * (44gCO2 / 1molCO2) = 49369.32g * (1kg / 1000g) = 49.6932 kgCO2
mCO2= 49.6932 kgCO2
Since there is so little information given, I will assume that we are at STP and i can use the conversion factor at STP--->> 22.4 Liters= 1 mol of gas
before we use this conversion, we need to convert the grams to moles using the molar mass of the molecule.
molar mass of Cl₂= 35.5 x 2= 71.0 g/ mol
177.3 g (1 mol/ 71.0 g)= 2.50 mol Cl₂
then we use the conversion to get the volume
2.50 mol Cl₂ (22.4 Liters/ 1 mol)= 55.9 Liters
