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Nezavi [6.7K]
4 years ago
14

Write balanced molecular equation for the reaction between nitric acid and calcium hydroxide. Express your answer as a chemical

equation. Identify all of the phases in your answer.
Chemistry
1 answer:
eimsori [14]4 years ago
6 0

<u>Answer:</u> The balanced chemical equation for the reaction of nitric acid and calcium hydroxide is written below.

<u>Explanation:</u>

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.

The balanced chemical equation for the reaction of nitric acid and calcium hydroxide follows:

2HNO_3(aq.)+Ca(OH)_2(aq.)\rightarrow Ca(NO_3)_2(aq.)+2H_2O(l)

By Stoichiometry of the reaction:

2 moles of nitric acid reacts with 1 mole of calcium hydroxide to produce 1 mole of calcium nitrate and 2 moles of water molecule.

Hence, the balanced chemical equation for the reaction of nitric acid and calcium hydroxide is written below.

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When doing an extraction, a student mixes 50 mL of 0.40 M benzoic acid (MW = 122 g/mole) with 30 mL of dichlormethane. After sep
Margarita [4]

Answer:

A. 2.44g

B. Kd = 3.2

Explanation:

Concentration of benzoic acid = 50mL = 0.05L

Molecular weight = 122 g/mol

Moles of benzoic acid before the extraction = mass/molecular weight of Benzoic acid

= molar concentration * volume

Moles of benzoic acid before the extraction = 0.05 * 0.4

= 0.02moles of benzoic acid before extraction.

Mass of benzoic acid = 0.02 * 122

= 2.44 g

Partition coefficient, Kd is defined as the ratio of concentration of a substance in an organic medium to the concentration of the substance in the aqueous medium.

Since 1.22g of Benzoic acid was in Dicholoroethane, therefore (2.44 - 1.22)g of benzoic acid was in water.

Mass concentration of benzoic acid in water = mass of benzoic in water/volume of water

= 1.22/0.05

= 24.4 g/L

Mass concentration of benzoic acid in Dicholoroethane = mass of benzoic in Dicholoroethane/volume of Dicholoroethane

= 1.22/0.03

= 40.67g/L

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= 1.67

7 0
4 years ago
Pls answer this asap
horsena [70]

Answer:

1. The enthalpy change for the backward reaction is –20 KJmol¯¹

2. The forward reaction is endothermic.

3. The activation energy for the forward reaction is +70 KJmol¯¹.

Explanation:

Considering the diagram given above, the following data were obtained:

1. The enthalpy change for the forward reaction being is +20 KJmol¯¹ and so, the enthalpy change for the backward reaction is –20 KJmol¯¹

2. The heat energy of the product is higher than that of the reactant. Therefore, the forward reaction is endothermic.

3. Activation energy is the minimum energy needed to be overcome in order for the reaction to proceed to product. It can be obtained from the energy profile diagram by considering the energy between the reactants and the peak.

For the question given above, Activation energy = 20 + 50

Activation energy = +70 KJmol¯¹

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3 years ago
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Answer:

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3 years ago
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3 years ago
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