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Bad White [126]
3 years ago
11

What's the smallest celestial body

Chemistry
1 answer:
finlep [7]3 years ago
6 0
Neutron Stars are considered as the smallest celestial bodies 
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An isothermal plug flow reactor is used to remove an environmental contaminant from polluted water via a 2nd-order reaction. A r
evablogger [386]

Answer:

The exact result is 82.5 min (close to c. 80 min)

Explanation:

Hello,

In the following picture you'll find the numerical procedure for this exercise.

- Take into account that the initial concentration and the velocity constant remain constant for the two mentioned scenarios.

Best regards.

5 0
3 years ago
A room that is 500 cm x 400 cm x 250 cm contains 65 kg of air. Determine the volume of air in the room and its density.
seropon [69]

Answer:

1.3g/L is the density of the air

Explanation:

The room is full of air, the space that the air occupy is:

500 cm x 400 cm x 250 cm = 5.00x10⁷ cm³

The density of a substance is defined as the ratio between the mass of the substance and the space that occupy. We can express the density of air in g/L:

<em>Grams air:</em>

65 kg  * (1000g / 1kg) = 65000g

<em>Liters:</em>

5.00x10⁷ cm³ * (1L / 1000cm³) = 50000L

<em>Density:</em>

65000g / 50000L =

<h3>1.3g/L is the density of the air </h3>
7 0
3 years ago
Hello! Can you please help me with this because I don’t get it at all. Thanks.
denpristay [2]

Answer:

Nov 28, 2019 - These templates were designed to help get you started. ... of each opportunity is clear to see, because the ones you send match not only my interests but my abilities. What you do is really motivating and keeps me uplifted in my job ... to thank you for all the support you've shown me throughout my career, ...

Explanation:

4 0
3 years ago
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Carbon dioxide is a common gas produced in burning describe a test for carbon dioxide gas​
TEA [102]

Answer:

burning gasoline

Explanation:

8 0
4 years ago
Asteroids in the main asteroid belt at certain distances from the Sun are in an orbital resonance with Jupiter, creating gaps in
tatyana61 [14]

Asteroids in the main asteroid belt at certain distances from the Sun are in an orbital resonance with Jupiter, the period of a belt asteroid in an 11:5 orbital resonance with Jupiter is mathematically given as

TA=5.4090years

<h3>What is the period of a belt asteroid in an 11:5 orbital resonance with Jupiter?</h3>

Generally, the equation for the ratio is mathematically given as

asteroid in an 11:5 orbital resonance= 11/5

Therefore, with Jupiter at

TJ=11.9years

Hence

11/4=TJ/TA

TA=5/11)*11.9

TA=5.4090years

Read more about Time

brainly.com/question/4931057

#SPJ1

5 0
2 years ago
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