Answer:
- There will be 1.23 moles of helium in the balloon at STP
Explanation:
1) <u>Initial conditions of the helium gas</u>:
- V = 20.0 liter
- p = 1.50 atm
- T = 25.0 °C = 25.0 + 273.15 K = 298.15 K
2) <u>Ideal gas equation</u>:
- pV = n RT
- p, V, and T are given above
- R is the Universal constant = 0.0821 atm-liter / ( K - mol)
- n is the unknown number of moles
3) <u>Solve for n</u>:
- n = 1.50 atm × 20.0 liter / (0.0821 atm-liter /k -mol ×298.15K)
4) <u>At STP:</u>
- STP stands for standard pressure and temperature.
- The amount (number of moles) of the gas will not change because the change of pressure and temperature, so the number of moles reamain the same: 1.23 mol.
To reduce a haloalkane, it has to be eliminated first. This is because 2 bromopropanes are a saturated compound that can not be reduced by a saturated compound. Dehydrohalogenation of the haloalkanes into the form of propene and hydrogen bromide can lead to the elimination. The propene is then reduced to propane.
Answer:
Water
Explanation:
Solid, liquids, and gases: Water can exist in several states, including ice (solid), water (liquid), and water vapor (gas). color (intensive)
density (intensive)
volume (extensive)
mass (extensive)
boiling point (intensive): the temperature at which a substance boils
melting point (intensive): the temperature at which a substance melts
To solve this problem, all we have to do it to make use of
the principle of ratio and proportion. We are given the following ratio:
1 part Chlorine / 10 parts Water
Now to determine the amount of chlorine needed for 15
ounces of water, all we have to do is to use proportion. Let us say that the
amount of Chlorine needed is x, therefore:
1 part Chlorine / 10 parts Water = x / 15 ounces Water
so,
1 / 10 = x / 15
Therefore calculating for x:
x = 15 / 10
<span>x = 1.5 ounces of Chlorine</span>
