Question

From a barrel of colored marbles you randomly select 7 blue, 5 yellow, 8 red, 4 green, and 6 purple marbles. Find the experimental probability of randomly selecting a marble that is either green or purple. Write your answer in simplest form.

Answer 1

Green is 4 and Purple is 6 so you put it in a fraction by adding all of them and the just green and purple so 10/30 simplified is 1/3.  

Answer 2

Answer: $\dfrac{1}{3}$

Step-by-step explanation:

Given: The total number of marbles = $7+5+8+4+6=30$

The number of green marbles = 4

The probability of selecting a green marble =$\dfrac{4}{30}$

The number of purple marbles = 6

The probability of selecting a purple marble =$\dfrac{6}{30}$

Now, the experimental probability of randomly selecting a marble that is either green or purple. is given by :-

$\text{P(either green or purple)}=\text{P(green)+P(purple)}\\\\\Rightarrow\ \text{P(either green or purple)}==\dfrac{4}{30}+\dfrac{6}{30}\\\\\Rightarrow\ \text{P(either green or purple)}==\dfrac{4+6}{30}\\\\\Rightarrow\ \text{P(either green or purple)}=\dfrac{10}{30}=\dfrac{1}{3}$