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USPshnik [31]
4 years ago
8

The force you have to overcome to start an object moving is _____

Physics
1 answer:
MAVERICK [17]4 years ago
3 0
The forece you have to overcome to start an object moving is called Inertia.
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A car goes from rest to a velocity of 108 km/h north in 10s what is the car's acceleration in m/s2
fomenos

initial velocity of the car given as

v_i = 0

final velocity is given as

v_f = 108 km/h

as we know that

1 km/h = 0.277 m/s

now we can convert final speed into m/s

v_f = 108 * 0.277 = 30 m/s

now acceleration is rate of change in velocity

a = \frac{v_f - v_i}{t}

a = \frac{30 - 0}{10}

a = 3 m/s^2

so the acceleration of the car is 3 m/s^2

7 0
3 years ago
Two balls with equal masses, m, and equal speed, v, engage in a head on elastic collision. what is the final velocity of each ba
Allushta [10]
The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.

- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
p_i = p_1-p_2 = mv-mv =0
So, the final momentum must be zero as well:
p_f = 0
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
p_f = mv_1 + mv_2 = 0
From which
v_1 = -v_2

- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is \frac{1}{2} mv^2. Therefore, the total kinetic energy before the collision is
K_i = \frac{1}{2} mv^2 +  \frac{1}{2} mv^2 = mv^2
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
K_f = K_i = mv^2 (1)
But the final kinetic energy, Kf, is also
K_f =  \frac{1}{2} mv_1^2 +  \frac{1}{2}mv_2^2
Substituting v_1 = -v_2 as we found in the conservation of momentum, this becomes
K_f = mv_2 ^2
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write 
mv_2^2 = mv^2

Therefore, the two final speeds of the balls are
v_2 = v
v_1 = -v_2 = -v

This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.

8 0
3 years ago
What is the magnitude and direction of the electric field atradiaConsider a coaxial conducting cable consisting of a conductingr
Alexxx [7]

Answer:

 E = 9.4 10⁶ N / C ,     The field goes from the inner cylinder to the outside

Explanation:

The best way to work this problem is with Gauss's law

             Ф = E. dA = qint / ε₀

 

We must define a Gaussian surface, which takes advantage of the symmetry of the problem. We select a cylinder with the faces perpendicular to the coaxial.

The flow on the faces is zero, since the field goes in the radial direction of the cylinders.

The area of ​​the cylinder is the length of the circle along the length of the cable

         dA = 2π dr L

          A = 2π r L

They indicate that the distance at which we must calculate the field is

         r = 5 R₁

         r = 5 1.3

         r = 6.5 mm

The radius of the outer shell is

         r₂ = 10 R₁

         r₂ = 10 1.3

         r₂ = 13 mm

         r₂ > r

When comparing these two values ​​we see that the field must be calculated between the two housings.

Gauss's law states that the charge is on the outside of the Gaussian surface does not contribute to the field, the charged on the inside of the surface is

         λ = q / L

         Qint = λ L

Let's replace

      E 2π r L = λ L /ε₀

       E = 1 / 2piε₀  λ / r

Let's calculate

         E = 1 / 2pi 8.85 10⁻¹²  3.4 10-12 / 6.5 10-3

         E = 9.4 10⁶ N / C

The field goes from the inner cylinder to the outside

5 0
3 years ago
Suppose our Sun is about to explode. In an effort to escape, we depart in a spacecraft at v=0.800 c and head toward the star Tau
Levart [38]

Considering a scenario in which the Sun is going to explode.

In order to escape the explosion, we depart in a spacecraft with a speed of v = 0.8c.

The star Tau Ceti is 12 life years away.

At the midpoint of the journey, the Sun as well as Tau Cetik explode. at the same instant.

Imagine a hermit who is immobile with respect to both the Sun and Tau Ceti and resides on an asteroid that is midway between both. He observes the blast waves of both explosions as our spaceship passes him. This observer concludes that the two stars blew up simultaneously because he believes both stars to remain stationary.

In the frame of reference, the Sun and Tau Ceti explode at the same time and will remain stationary.

Learn more about the frame of reference here:

brainly.com/question/10962551

#SPJ4

8 0
2 years ago
How dose storing waste underground can be effected by ground water in aquifers<br><br>​
DiKsa [7]

Answer:

it can contaminate the water

Explanation:

I hope this helps ;)

7 0
3 years ago
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