Long periods of unusually low precipitation are called?

Which of the following is the best example of Newton's second law? A. A rolling ball comes to a stop because the forces of frict

fgiga [73]

Answer:

B. the acceleration of a skydiver depends upon the force of gravity and wind resistance

Explanation:

Newtons second law of motion states that: the force (F) acting upon an object is directly proportional to the mass (M) of the object and the acceleration (a).

Basically this law states that the acceleration of a body is dependent on the force and mass of the body. If the force exerted on the body changes the acceleration will also change. and if the mass of the body changes, the acceleration will also be affected

from the options, the only option that refers to acceleration is option B

6 0

3 years ago

An object with a mass of m = 122 kg is suspended by a rope from the end of a uniform boom with a mass of M = 74.9 kg and a lengt

creativ13 [48]

The horizontal rope is under 7,019.4 N of tension.

The pulling force conveyed axially by a string, cable, chain, or another similar device, or by the ends of a rod, is referred to as tension.

The action-reaction pair of forces acting at the ends of the element can also be referred to as tension.

The tension unit is the Newton.

the horizontal rope is tense.

The following formula is used to determine the horizontal rope's tension:

Apply the torque principle;

Mg (L/2) sin + mg L sin = T(L/2) cos

M + 2mg sin/cos = T

(M + 2m)g tan = T

let θ = 66⁰ (The question should include this value)

(M + 2m)g tan = T

T = (74.9 + 2 x 122)(9.8) (tan 66)

T = 7,019.4 N

7,019.4 N is the tension in the horizontal rope.

Learn more about tension here: brainly.com/question/918617

#SPJ1

7 0

2 years ago

A stubborn, 100 kgkg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around

jolli1 [7]

Answer:

No, the farmer is not able to move the mule.

Explanation:

Mass =100 kg

Force=F=800 N

The coefficient between the mule and the ground= $\mu_s=0.8$

$\mu_k=0.5$

Static friction force,f= $\mu N$

Normal force=N=mg

Static friction force,f= $\mu_s mg=0.8\times 100\times 9.8=784 N$

Using $g=9.8m/s^2$

F<f

Static friction force is greater than applied force.

Therefore , the farmer is not able to move the mule.

4 0

3 years ago

Helium gas is compressed by an adiabatic compressor from an initial state of 14 psia and 50°F to a final temperature of 320°F in

iVinArrow [24]

Answer:

The value is $P_2 = 40.54 \ psla$

Explanation:

From the question we are told that

The initial pressure is $P_1 = 14\ psla$

The initial temperature is $T_1 = 50 \ F = (50 - 32) * [\frac{5}{9} ] + 273 = 283 \ K$

The final temperature is $T_2 = 320 \ F = (320 - 32) * [\frac{5}{9} ] + 273 =433 \ K$

Generally the equation for adiabatic process is mathematically represented as

$PT^{\frac{\gamma}{1- \gamma} } = Constant$

=> $P_1T_1^{\frac{\gamma}{1- \gamma} } = P_2T_2^{\frac{\gamma}{1- \gamma} }$

Generally for a monoatomic gas $\gamma = \frac{5}{3}$

So

$14 * 283^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} } =P_2 * 433^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} }$

=> $14 * 283^{-2.5} =P_2 * 433^{-2.5}$

=> $P_2 = 40.54 \ psla$

8 0

2 years ago

What mass of a material with density Ï is required to make a hollow spherical shell having inner radius r1 and outer radius r2?

inysia [295]

<span>Yes, there are! r1 and r2 are numbers. The volume of the hollow shell is 4 π 3 ( r 3 1 − r 3 2 ) 4π3(r13−r23). Now multiply by ρ to get the mass.</span>

3 0

3 years ago