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d1i1m1o1n [39]
3 years ago
10

Long periods of unusually low precipitation are called?

Physics
1 answer:
DiKsa [7]3 years ago
6 0
I think it is called a drought but i would look it up
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Explain why a roller coaster’s second hill cannot be taller than the first hill.
max2010maxim [7]
There will not be enough momentum from the first hill to cross another hill if he same or larger size because of the way potential energy and kinetic energy works it will not be able go as high as it could go on he fist hill.
4 0
2 years ago
Read 2 more answers
Which of the following is the same in all frames of reference?
Ksju [112]
The correct option is B.
The length of an object, the mass of an object and the rate of time passage for an object can change depending on the situation which the object is subject to. For instance in space, the mass and the velocity of an object usually change. But, the value of the speed of light in the space is the same for all observers regardless of the motion of an object, that is, the speed of light is a constant.<span />
4 0
3 years ago
In a photoelectric experiment, you shine light onto an electrode and record a current of 25 μA. When you apply +500 mV to the el
kkurt [141]

Answer:

2.083 V.

Explanation:

Stopping potential is the potential that is required to stop the current to zero . This potential is applied externally to oppose the potential created by the photoelectric effect . It gives the measure the photoelectric potential being generated .

Here current drops to 25 μA to 19 μA by a potential of 500mV

Change in current

= 25 - 19 = 6 μA

Voltage requirement for unit reduction in current

= 500 / 6 μA

To reduce current 0f 25 μA

requirement of V = (500 / 6 )  x 25 =   2083.33 mV = 2.083 V.

7 0
3 years ago
Ayuda por favor (archivo adjunto) con un ejercicio de expresión sobre periodo de oscilación de esta figura:
vodka [1.7K]

Answer:

nolo se

Explanation:

no lo se

8 0
2 years ago
It is necessary to determine the specific heat of an unknown object. The mass of the object is 201.0 g. It is determined experim
navik [9.2K]
Mass = 0.201kg
Energy = 15J
temperature change = 10C

Energy(E) = mass(m) × specific heat capacity(c) × temperature change(θ)

we can rearrange this to make specific heat capacity the subject

c =\frac{E}{m\theta}

c =\frac{15}{2.01}
c =7.46268657

6 0
3 years ago
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