A 2.45 g table tennis ball has the KE of 31.5 J. At what velocity is the tennis ball traveling?
2 answers:
Answer:
160.35 m/s
Explanation:
Kinetic energy of a body depends on the mass (m) of the body and the speed (v) with it is moving. It is the energy possessed by body due to virtue of its motion.
K.E. = 0.5 m v²
It is given that, m = 2.45 g = 2.45 ×10⁻³ kg
K.E. = 31.5 J
Thus, the tennis ball is moving with the velocity of 160.35 m/s.
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Answer:
The maximum potential difference is 186.02 x 10¹⁵ V
Explanation:
formula for calculating maximum potential difference
where;
Ke is coulomb's constant = 8.99 x 10⁹ Nm²/c²
k is the dielectric constant = 2.3
b is the outer radius of the conductor = 3 mm
a is the inner radius of the conductor = 0.8 mm
λ is the linear charge density = 18 x 10⁶ V/m
Substitute in these values in the above equation;
Therefore, the maximum potential difference this cable can withstand is 186.02 x 10¹⁵ V
In an inelastic collision, only momentum is conserved, while energy is not conserved.
1) Velocity of the nail and the block after the collision
This can be found by using the total momentum after the collisions:
where
m=0.1 kg is the mass of the nail
M=10 kg is the mass of the block of wood
Rearranging the formula, we find
, the velocity of the nail and the block after the collision:
2) The velocity of the nail before the collision can be found by using the conservation of momentum. In fact, the total momentum before the collision is given only by the nail (since the block is at rest), and it must be equal to the total momentum after the collision:
Rearranging the formula, we can find
, the velocity of the nail before the collision:
1) Velocity of the nail and the block after the collision
This can be found by using the total momentum after the collisions:
where
m=0.1 kg is the mass of the nail
M=10 kg is the mass of the block of wood
Rearranging the formula, we find
2) The velocity of the nail before the collision can be found by using the conservation of momentum. In fact, the total momentum before the collision is given only by the nail (since the block is at rest), and it must be equal to the total momentum after the collision:
Rearranging the formula, we can find