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Brilliant_brown [7]
3 years ago
9

A 2.45 g table tennis ball has the KE of 31.5 J. At what velocity is the tennis ball traveling?

Physics
2 answers:
MAVERICK [17]3 years ago
8 0

Answer:

160.35 m/s

Explanation:

Kinetic energy of a body depends on the mass (m) of the body and the speed (v) with it is moving. It is the energy possessed by body due to virtue of its motion.

K.E. = 0.5 m v²

It is given that, m = 2.45 g = 2.45 ×10⁻³ kg

K.E. = 31.5 J

v = \sqrt{\frac{2K.E.}{m}} = \sqrt{2\times 31.5}{2.45 \times 10^{-3}}=160.35 m/s

Thus, the tennis ball is moving with the velocity of 160.35 m/s.

Ket [755]3 years ago
3 0
KE =
\frac{1}{2} mv {}^{2}
Convert g in kg
Find v:
2KE = mv^2
v=√2KE/m
v=√2*31.5/0.00245
v=160 m/s

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Consider a container of oxygen gas at a temperature of 23°C that is 1.00 m tall. Compare the gravitational potential energy of a
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Answer:

Yes, it is reasonable to neglect it.

Explanation:

Hello,

In this case, a single molecule of oxygen weights 32 g (diatomic oxygen) thus, the mass of kilograms is (consider Avogadro's number):

m=1molec*\frac{1mol}{6.022x10^{23}molec} *\frac{32g}{1mol}*\frac{1kg}{1000g}=5.31x10^{-26}kg

After that, we compute the potential energy 1.00 m above the reference point:

U=mhg=5.31x10^{-26}kg*1.00m*9.8\frac{m}{s^2}=5.2x10^{-25}J

Then, we compute the average kinetic energy at the specified temperature:

K=\frac{3}{2}\frac{R}{Na}T

Whereas N_A stands for the Avogadro's number for which we have:

K=\frac{3}{2} \frac{8.314\frac{J}{mol*K}}{6.022x10^{23}/mol}*(23+273)K\\ \\K=6.13x10^{-21}J

In such a way, since the average kinetic energy energy is about 12000 times higher than the potential energy, it turns out reasonable to neglect the potential energy.

Regards.

8 0
4 years ago
A skydiver has a mass of 65 kg.<br> Calculate the weight of the skydiver.
Vinil7 [7]
F=m*a
F=65 kg *9.8 m/s^2
F=637 N (Newtons) — this is the weight
3 0
3 years ago
When will heat transfer within a liquid stop? (25 points)
exis [7]
Choice C.
That's when convection stops.
3 0
3 years ago
Place the following into scientific notation...(.000635)<br> *
AleksAgata [21]
6.35x10^-4 OR 6.3x10-4 (if only one decimal number is allowed)
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Two parallel wires carry currents in the same direction. If the currents in the wires are 1A and 4A and the wires are 5 m apart.
serious [3.7K]

Answer:

1.6\times 10^{-7} N

2.4\times 10^{-7} N

Explanation:

i_{1} = 1 A

i_{2} = 4 A

r = distance between the two wire = 5 m

F = Force per unit length acting between the two wires

Force per unit length acting between the two wires is given as

F = \frac{\mu _{o}}{4\pi }\frac{2i_{1}i_{2}}{r}

F = (10^{-7})\frac{2(1)(4)}{5}

F = 1.6\times 10^{-7} N

r'} = distance of each wire from the midpoint = 2.5 m

Magnetic field midway between the two wires is given as

B = \frac{\mu _{o}}{4\pi } \left \left ( \frac{2i_{2}}{r'} \right - \frac{2i_{1}}{r'} \right \right ))

B = (10^{-7}) \left \left ( \frac{2(4)}{2.5} \right - \frac{2(1)}{2.5} \right \right ))

B = 2.4\times 10^{-7}

5 0
3 years ago
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