We are asked to determine the value of a such that the function f(x) = ax^2 + 5 is fit for the point given (-1,2). In this case, we substitute 2 to y and -1 to x. The result is then 2 = a*(-1)^2 + 5 ; 2 = a + 5; a is then equal to -3
The slope intercept form is y=mx+b
in this case y=-x
y=(-1)x + 0
so the slope m=-1 and y-intercept which is b is 0
Ok then um so ya ok thx for the points though
Hi!
Two negatives make a positive, so this can be rewritten as
-7+2.5
The answer is D. -7+2.5
Hope this helps! :)
-Peredhel
Answer:
A. No
Step-by-step explanation:
y = 2x + 4
(5) = 2(1) + 4
5 = 2 + 4
5 = 6 (false statement)
