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mars1129 [50]
3 years ago
13

Given n2 (g) + 3 h2 (g) 2 nh3 (g), which scenario will allow you to eventually reach an equilibrium mixture involving these chem

icals?
Chemistry
1 answer:
mash [69]3 years ago
5 0

<span>The only scenario that will allow you to reach an equilibrium mixture involving these chemicals is to place NH3 into a sealed vessel. This reaction requires pressures between 2100, 3600 psi, and temperatures between 300 and 550 degree Celsius. With this given temperature and pressure, the ammonia naturally decomposes into nitrogen and hydrogen gas at the same rate. When this happen, the concentrations of these chemicals become constant and the system is said to be at equilibrium.</span>

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_Na+ Cl2 - -&gt; _NaCl<br><br> A 2,4<br> B 1,2<br> C 3,3<br> D 2,2
Natali [406]

Answer:

D 2,2

Explanation:

We can see that there are 2 chlorines on the reactant side so there has to be a 2 on the product side

Now we have Na + Cl2 --> 2NaCl

The problem now is that there are 2 sodiums on the product side so add a 2 to the Na on the reactant side

2Na + Cl2 --> 2NaCl

Now it's balanced!

4 0
2 years ago
How many moles of CaCl₂ are required to produce 45.97 grams of NaCl?
marin [14]
Answer is 0.7866187543

6 0
2 years ago
1gallon=3.79 liters, The gas tank of a car holds 15 gallons.if you were traveling in Europe how many liters if petrol would you
Andrei [34K]
For an approximate result, multiply the volume value by 3.785
Answer ≈ 56.7812
6 0
3 years ago
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0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati
erastova [34]

Answer:

[Ag^{+}]=4.2\times 10^{-2}M

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

[K2CrO4] = 0.10 M

Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

BaCrO_4 (s)\leftrightharpoons  Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ba^{2+}][CrO_{4}^{2-}]

1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]

[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}

Now,

Ag_{2}CrO_4(s) \leftrightharpoons  2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]

1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})

[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}

[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

                       

7 0
3 years ago
What do you think the density of a person might be? Explain
Verizon [17]
So this can explain the density of a person very clearly.

7 0
2 years ago
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