Answer:
180 meters
Explanation:
Josh walks 6 meters to the right and the 6 meters back. This means that in one time, Josh walks a total distance of 6+6 = 12 meters
Now, we are given that Josh walks this same distance 15 times.
Therefore, we will multiply this distance by 15 to get the total distance that he walks as follows:
Total distance = 12*15 = 180 meters
Based on the above calculations, Josh walks 180 meters over the course of the class
Hope this helps :)
I believe it's technically referred to as the Normal force.
However I like to think of it as the reaction force, as it is the force that is a result of obeying Newton's 3rd law ("<span>For every action, there is an equal and opposite reaction"). The upward force from the ground is the reaction to the downward force of gravity.</span>
Answer:
50m/s²
Explanation:
cross muliplyy write down the values acceleration and force
-- Looking at the dots casually, they look green because they absorb all other
colors of light, and only green light is left to proceed to your eyes. (In order for
this to work, there has to be some green in the light shining on the dots.
Daylight and most light bulbs work fine.)
-- The filter looks red because it absorbs all other colors of light, and only
the red light is left to pass through the filter and come out on the other side.
-- When the green light from the dots hits the red filter, it's absorbed in the
filter, and there's no light left to come out on the other side.
If you're looking through the filter at the dots, they look <em>black</em>.
Answer:
0.71 m/s
Explanation:
We find the time it takes the stone to hit the water.
Using y = ut - 1/2gt² where y = height of bridge, u = initial speed of stone = 0 m/s, g = acceleration due to gravity = -9.8 m/s² (negative since it is directed downwards)and t = time it takes the stone to hit the water surface.
So, substituting the values of the variables into the equation, we have
y = ut - 1/2gt²
82.2 m = (0m/s)t - 1/2( -9.8 m/s²)t²
82.2 m = 0 + (4.9 m/s²)t²
82.2 m = (4.9 m/s²)t²
t² = 82.2 m/4.9 m/s²
t² = 16.78 s²
t = √16.78 s²
t = 4.1 s
This is also the time it takes the raft to move from 5.04 m before the bridge to 2.13 m before the bridge. So, the distance moved by the raft in time t = 4.1 s is 5.04 m - 2.13 m = 2.91 m.
Since speed = distance/time, the raft's speed v = 2.91 m/4.1 s = 0.71 m/s
