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Arada [10]
3 years ago
9

If an experiment involves a large volume of liquid a _______ would most likely be used to hold it.

Physics
2 answers:
Marianna [84]3 years ago
7 0

Answer:

D: Beaker

Explanation:

The beaker has the largest capacity for volume among these options. A beaker is usually used to hold stock liquid, while it is poured into smaller containers, such as test tubes.

Test tubes hold the final amount usually used in the chemical reactions.

Graduated cylinders are usually used to measure certain liquids (mostly from beakers) to obtain precise amounts of a substance.

Hot plates are used to heat substances and cannot hold liquids.

Grace [21]3 years ago
3 0
The answer is d a beacker
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Derive an expression for the block's centripetal acceleration ac in terms of m , θ , and physical constants, as appropriate
maxonik [38]

The expression for the block's centripetal acceleration is derived as ω²r or v²/r.

<h3>What is centripetal acceleration?</h3>

The centripetal acceleration of an object is the inward or radial acceleration of an object moving in a circular path.

The expression for the block's centripetal acceleration is derived as follows;

ω = dθ/dt

where;

  • ω is the angular speed
  • θ is the angular displacement
  • t is the time of motion

ac = ω²r

where;

  • r is the radius of the circular path

Also, ω = v/r

ac = (v/r)²r

ac = v²/r

Thus, the expression for the block's centripetal acceleration is derived as ω²r or v²/r.

Learn more about centripetal acceleration here: brainly.com/question/79801

7 0
2 years ago
The magnitude of the drag force of air resistance on a certain 20kg object is proportional to its speed. If the object has a ter
Anna11 [10]
Given:
object = 20kg
terminal speed of object = 80 m/s

According to the problem, drag force is proportional to speed, so Fd = kv ; k is some constant
At terminal velocity Vt: Fg = Fdmg = kVtk = mg / Vt = (20.0)(9.8)/(80.0) = 2.45 kg/s
<span>Fd = kv = 2.45v</span>
Fd = 2.45 (30.0) = 73.5 N
8 0
4 years ago
If the photon scatters in the backward direction, what is the magnitude of the linear momentum of the electron just after the co
Strike441 [17]
Momentum is a vector quantity, and is always conserved. Whenever a collision occurs between two objects, the objects behave under the principle of conservation of momentum. Therefore, if an object moves in the direction opposite to its original direction after a collision, then this indicates that the momentum of the colliding object was greater than the object under consideration. 
8 0
3 years ago
A tennis ball is dropped from 1.43 m above the
Rudiy27

Answer:

-5.29 m/s

Explanation:

Given:

y₀ = 1.43 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.43 m)

v = -5.29 m/s

4 0
4 years ago
In which of the following cases is work being done on an object? Question 2 options: Pushing against a locked door Carrying a bo
Serggg [28]

As we know that work done is defined as product of force and displacement in the direction of applied force

so we can say it is

W = F.d

or we can say

W = Fdcos\theta

so we will have following options

A)Pushing against a locked door

There is no work done in above case as there will be no displacement in that case so work done is ZERO

B) Carrying a box down a corridor

While we move done and carrying a box then work done by gravity on the box while our work done is negative work.

C) Pulling a trailer up a hill

In above case our work done to pull a box up a hill is positive work as we need to work against gravity

D)  Suspending a heavy weight with a strong chain

During suspension there is no displacement so there will be no work done in above case

so correct answer will be

<em>Pulling a trailer up a hill</em>


6 0
4 years ago
Read 2 more answers
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