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hichkok12 [17]
3 years ago
13

If 1.8 1016 electrons enter a light bulb in 3 milliseconds, what is the magnitude of the electron current at that point in the c

ircuit?
Physics
1 answer:
Mice21 [21]3 years ago
7 0

Answer:

I = 0.96 A

Explanation:

No of electrons, n=1.8\times 10^{16}

Time, t = 3 ms = 3\times 10^{-3}\ s

We need to find the electric current. We know that electric charge per unit time is equal to the electric current.

I=\dfrac{q}{t}

q = ne (Quantization of electric charge)

I=\dfrac{ne}{t}\\\\I=\dfrac{1.8\times 10^{16}\times 1.6\times 10^{-19}}{3\times 10^{-3}}\\\\I=0.96\ A

So, the electric current is 0.96 A.

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A particle with mass 1.81*10^-3kg and a charge of 1.22*10^-8C has, at a given instant, a velocity v= (3.0*10^4 m/s)j.
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Answer:

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Direction: negative

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m = 1.81 × 10^(−3) kg

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2 years ago
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Hey /人 ◕ ‿‿ ◕ 人\
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Answer:

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