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3 years ago

How does a projectile differ from an object in free fall?

2 answers:

8 0

A projectile has some form of thrust to propel it in the desired direction, while an object in free fall has no extra force guiding/propelling it

Alja [10]3 years ago

8 0

A projectile is any object upon which the only force is gravity, Projectiles travel with a parabolic trajectory due to the influence of gravity, ... The vertical velocity of a projectile changes by 9.8 m/s each second, The horizontal motion of a projectile is independent of its vertical motion.

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

aev [14]

A. To express large and small numbers

5 0

3 years ago

Read 2 more answers

Why cant your rocket could never reach the speed of light?

Oksanka [162]

Answer:

The length of the object would shrink to zero which is not possible.

Explanation:

A rocket or any body cannot reach the speed of light because according to theory of relativity the and the Lorentz factor the length of the object would shrink to zero and the time dilation for that body would be infinite.

The Lorentz factor is given as:

$\gamma=\frac{1}{\sqrt{\frac{v^2}{c^2} } }$

where:

v = speed of the moving object

c = speed of light

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3 years ago

An induced charge is when charged particles can be attracted to neutral objects.<br> True or false?

Sindrei [870]

Answer:

the answer is true Induction charging is a method used to charge an object without actually touching the object to any other charged object.

Explanation:

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3 years ago

You split wood with an ax. How would you change the ax to make splitting the wood easier? You would increase mechanical advantag

alex41 [277]

I think you forgot to give the choices along with the question. I am answering the question based on my knowledge and research. You would increase mechanical advantage by <span>making the blade longer from the cutting edge. I hope that this is the answer that has actually come to your desired help.</span>

6 0

3 years ago

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A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 6 ft from the path and is kept fo

BARSIC [14]

We are given that,

$\frac{dx}{dt} = 4ft/s$

We need to find $\frac{d\theta}{dt}$ when $x=8ft$

The equation that relates x and $\theta$ can be written as,

$\frac{x}{6} tan\theta$

$x = 6tan\theta$

Differentiating each side with respect to t, we get,

$\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}$

$\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}$

$\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}$

Replacing the value of the velocity

$\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2$

$\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta$

The value of $cos \theta$ could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to

$cos\theta = \frac{6}{10}$

$\frac{d\theta}{dt} = \frac{8}{3} (\frac{6}{10})^2$

$\frac{d\theta}{dt} = \frac{24}{25}$

Search light is rotating at a rate of 0.96rad/s

4 0

2 years ago