How does a projectile differ from an object in free fall?
2 answers:
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Answer:
E = 1580594.95 N/C
Explanation:
To find the electric field inside the the non-conducting shell for r=11.2cm you use the Gauss' law:
(1)
dS: differential of the Gaussian surface
Qin: charge inside the Gaussian surface
εo: dielectric permittivity of vacuum = 8.85 × 10-12 C2/N ∙ m2
The electric field is parallel to the dS vector. In this case you have the surface of a sphere, thus you have:
(2)
Qin is calculate by using the charge density:
(3)
Vin is the volume of the spherical shell enclosed by the surface. a is the inner radius.
The charge density is given by:
Next, you use the results of (3), (2) and (1):
Finally, you replace the values of all parameters, and for r = 11.2cm = 0.112m you obtain:
hence, the electric field is 1580594.95 N/C
Answer:
Use the method on the image and solve it.
