A) you can't see far ahead
mass of bullet, m = 21 g = 0.021 kg
distance, s = 114 cm = 1.14 m
final velocity, v = 1180 m/s
initial velocity, u = 0
Let F be the force .
By use of work energy theorem
Work done = change in kinetic energy
F x s = 1/2 m v² - 1/2 mu²
F x 1.14 = 0.5 x 0.021 x 1180 x 1180
F = 12824.74 N
8.90 x 10^-3
It has to be 10^-3 (ten to the negative three) because when you move the decimal back to it's proper place you are moving it to the left.
and it has to be 8.90 because you have to observe correct sig figs. The 0 at the end of the number is significant because it is at the end of the number AND to the right of the decimal point.
to calculate the electric field, we use the equation below
where v=voltage, d= distance and E=electric field.
Hence we have
b.the expression for the charge density is expressed as
where ξ is the permitivity of air with a value of 8.85*10^-12C^2/N.m^2
If we insert the values we have
from the expression for the capacitance
if we substitute values we arrive at
d. To calculate the charge on each plate, we use the formula below
Try the solutions described in the attached picture, note the answers are marked with green colour.