**Answer:**

12824.74 N

**Explanation:**

mass of bullet, m = 21 g = 0.021 kg

distance, s = 114 cm = 1.14 m

final velocity, v = 1180 m/s

initial velocity, u = 0

Let F be the force .

By use of work energy theorem

Work done = change in kinetic energy

F x s = 1/2 m v² - 1/2 mu²

F x 1.14 = 0.5 x 0.021 x 1180 x 1180

F = 12824.74 N

**Answer:**

8.90 x 10^-3

**Explanation:**

8.90 x 10^-3

It has to be 10^-3 (ten to the negative three) because when you move the decimal back to it's proper place you are moving it to the left.

and it has to be 8.90 because you have to observe correct sig figs. The 0 at the end of the number is significant because it is at the end of the number AND to the right of the decimal point.

**Answer:**

a. 11.5kv/m

b.102nC/m^2

c.3.363pF

d. 77.3pC

**Explanation:**

Data given

to calculate the electric field, we use the equation below

V=Ed

where v=voltage, d= distance and E=electric field.

Hence we have

b.the expression for the charge density is expressed as

σ=ξE

where ξ is the permitivity of air with a value of 8.85*10^-12C^2/N.m^2

If we insert the values we have

c.

from the expression for the capacitance

if we substitute values we arrive at

d. To calculate the charge on each plate, we use the formula below

Try the solutions described in the attached picture, note the answers are marked with green colour.