I would say C but I’m not complete sore
Answer:
Speed of the electron will be ![v=5.896\times 10^7m/sec](https://tex.z-dn.net/?f=v%3D5.896%5Ctimes%2010%5E7m%2Fsec)
Explanation:
We have given that charge on electron ![e=1.6\times 10^{-19}C](https://tex.z-dn.net/?f=e%3D1.6%5Ctimes%2010%5E%7B-19%7DC)
Mass of electron ![m=9.11\times 10^{-31}kg](https://tex.z-dn.net/?f=m%3D9.11%5Ctimes%2010%5E%7B-31%7Dkg)
Potential difference = ![V=9.9KV=9.9\times 10^3volt](https://tex.z-dn.net/?f=V%3D9.9KV%3D9.9%5Ctimes%2010%5E3volt)
Now according to energy conservation ![eV=\frac{1}{2}mv^2](https://tex.z-dn.net/?f=eV%3D%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
![1.6\times 10^{-19}\times 9.9\times 10^3=\frac{1}{2}\times 9.11\times 10^{-31}v^2](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%209.9%5Ctimes%2010%5E3%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%209.11%5Ctimes%2010%5E%7B-31%7Dv%5E2)
![v=5.896\times 10^7m/sec](https://tex.z-dn.net/?f=v%3D5.896%5Ctimes%2010%5E7m%2Fsec)
Answer: d = 2,079 m
Explanation:
5.5 m/s(6.3 min)(60 s/min) = 2,079 m
Given :
A 0.50-kg mass is attached to a spring of spring constant 20 N/m along a horizontal, frictionless surface.
The object oscillates in simple harmonic motion and has a speed of 1.5 m/s at the equilibrium position.
To Find :
At what location are the kinetic energy and the potential energy the same.
Solution :
Let, at location x from the equilibrium position the kinetic energy and the potential energy the same.
So,
Hence, this is the required solution.
The tendency of a material to oppose the flow of charge is called: B) resistance