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disa [49]
3 years ago
7

A roller coaster car is going over the top of a 18-m-radius circular rise. at the top of the hill, the passengers "feel light,"

with an apparent weight only 50 % of their true weight.

Physics
2 answers:
Mashutka [201]3 years ago
8 0

The solution for this problem is:

If they feel 50% of their weight that means that the centripetal force is also 50% of their weight 1g - 0.5g = 0.5g 


Then 0.5* 9.8m/s² * 18m = 88.2 would be v² 

Then get the square root, the answer would be:
and v = 9.391 m/s is the answer.

ddd [48]3 years ago
7 0

The speed of roller coaster car is about 9.4 m/s

\texttt{ }

<h3>Further explanation</h3>

Centripetal Acceleration can be formulated as follows:

\large {\boxed {a = \frac{ v^2 } { R } }

<em>a = Centripetal Acceleration ( m/s² )</em>

<em>v = Tangential Speed of Particle ( m/s )</em>

<em>R = Radius of Circular Motion ( m )</em>

\texttt{ }

Centripetal Force can be formulated as follows:

\large {\boxed {F = m \frac{ v^2 } { R } }

<em>F = Centripetal Force ( m/s² )</em>

<em>m = mass of Particle ( kg )</em>

<em>v = Tangential Speed of Particle ( m/s )</em>

<em>R = Radius of Circular Motion ( m )</em>

Let us now tackle the problem !

\texttt{ }

<u><em>Complete Question:</em></u>

<em>A roller coaster car is going over the top of a 18-m-radius circular rise. at the top of the hill, the passengers "feel light," with an apparent weight only 50% of their true weight. How fast is the coaster moving?</em>

<u>Given:</u>

radius of circular motion = R = 18 m

weight of passengers = w

apparent weight of passengers = N = 50%w

<u>Asked:</u>

speed of roller coaster car = v = ?

<u>Solution:</u>

\Sigma F = m \frac{v^2}{R}

w - N = m \frac{v^2}{R}

w - 50\% w = m \frac{v^2}{R}

50\% w = m \frac{v^2}{R}

50\% mg = m \frac{v^2}{R}

\frac{1}{2} g = \frac{v^2}{R}

v^2 = \frac{1}{2} gR

v = \sqrt { \frac{1}{2} g R }

v = \sqrt { \frac{1}{2} \times 9.8 \times 18}

v = \frac{21}{5} \sqrt{5} \texttt{ m/s}

\boxed{v \approx 9.4 \texttt{ m/s}}

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Circular Motion

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2 a A pile of 60 sheets of paper is 6 mm high. Calculate the average thickness of a sheet of the paper.
fiasKO [112]

The average thickness of a sheet of the paper is 0.1 mm.

The number of ice blocks that can be stored in the freezer is 80 blocks of ice.

<h3>Average thickness of a sheet of the paper</h3>

The average thickness of a sheet of the paper is calculated as follows;

average thickness = 6 mm/60 sheets = 0.1 mm /sheet

Thus, the average thickness of a sheet of the paper is 0.1 mm.

<h3>Volume of each block of ice</h3>

Volume = 10 cm x 10 cm x 4 cm

Volume = 400 cm³

<h3>Volume of the freezer</h3>

Volume = 40 cm x 40 cm x 20 cm = 32,000 cm³

<h3>Number of ice blocks that can be stored</h3>

n = 32,000 cm³/400 cm³

n = 80 blocks of ice

Thus, the number of ice blocks that can be stored in the freezer is 80 blocks of ice.

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#SPJ1

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Which of the following types of rocks are likely to be formed due to heat and pressure? Sedimentary rock only Metamorphic rock o
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Read 2 more answers
4. How much work is done when you lift a 25 N box up to a 2 m shelf?
Semmy [17]

Answer:

<h2>50 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question

force = 25 N

distance = 2 m

We have

workdone = 25 × 2 = 50

We have the final answer as

<h3>50 J</h3>

Hope this helps you

6 0
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