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disa [49]
3 years ago
7

A roller coaster car is going over the top of a 18-m-radius circular rise. at the top of the hill, the passengers "feel light,"

with an apparent weight only 50 % of their true weight.

Physics
2 answers:
Mashutka [201]3 years ago
8 0

The solution for this problem is:

If they feel 50% of their weight that means that the centripetal force is also 50% of their weight 1g - 0.5g = 0.5g 


Then 0.5* 9.8m/s² * 18m = 88.2 would be v² 

Then get the square root, the answer would be:
and v = 9.391 m/s is the answer.

ddd [48]3 years ago
7 0

The speed of roller coaster car is about 9.4 m/s

\texttt{ }

<h3>Further explanation</h3>

Centripetal Acceleration can be formulated as follows:

\large {\boxed {a = \frac{ v^2 } { R } }

<em>a = Centripetal Acceleration ( m/s² )</em>

<em>v = Tangential Speed of Particle ( m/s )</em>

<em>R = Radius of Circular Motion ( m )</em>

\texttt{ }

Centripetal Force can be formulated as follows:

\large {\boxed {F = m \frac{ v^2 } { R } }

<em>F = Centripetal Force ( m/s² )</em>

<em>m = mass of Particle ( kg )</em>

<em>v = Tangential Speed of Particle ( m/s )</em>

<em>R = Radius of Circular Motion ( m )</em>

Let us now tackle the problem !

\texttt{ }

<u><em>Complete Question:</em></u>

<em>A roller coaster car is going over the top of a 18-m-radius circular rise. at the top of the hill, the passengers "feel light," with an apparent weight only 50% of their true weight. How fast is the coaster moving?</em>

<u>Given:</u>

radius of circular motion = R = 18 m

weight of passengers = w

apparent weight of passengers = N = 50%w

<u>Asked:</u>

speed of roller coaster car = v = ?

<u>Solution:</u>

\Sigma F = m \frac{v^2}{R}

w - N = m \frac{v^2}{R}

w - 50\% w = m \frac{v^2}{R}

50\% w = m \frac{v^2}{R}

50\% mg = m \frac{v^2}{R}

\frac{1}{2} g = \frac{v^2}{R}

v^2 = \frac{1}{2} gR

v = \sqrt { \frac{1}{2} g R }

v = \sqrt { \frac{1}{2} \times 9.8 \times 18}

v = \frac{21}{5} \sqrt{5} \texttt{ m/s}

\boxed{v \approx 9.4 \texttt{ m/s}}

\texttt{ }

<h3>Learn more</h3>
  • Impacts of Gravity : brainly.com/question/5330244
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
  • The Acceleration Due To Gravity : brainly.com/question/4189441

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Circular Motion

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Workdone = 20 Joules

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First of all, we would find the spring constant using the formula;

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Next, we find the work done;

Workdone = ½ke²

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A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.080
deff fn [24]

Answer:

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v = \omega \frac{L}{2}

v = 4.32 (0.45)

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3 0
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