Answer:
6.575
Explanation:
T1 = 30C = 30 + 273 = 303 K
T2 = - 10 C = - 10 + 273 = 263 K
The coefficient of performance of heat pump
k = T2 / (T1 - T2)
k = 263 / (303 - 263) = 6.575
The situation is impossible mainly because we can't see Figure P6.10 .
It would undoubtedly be the same story on an another planet, until we
see the figure and understand what's going on.
When they meet the 40-kg boy would have moved a distance of 6 m.
<h3>Distance moved by the 40 kg boy</h3>
Apply the principle of center mass;
Take the 40 kg mass as the reference point;
X(40 kg) = (40kg x 0 + 60kg x 10 m)/(40 kg + 60 kg)
X(40 kg) = (600)/(100)
X(40 kg) = 6 m
Thus, when they meet the 40-kg boy would have moved a distance of 6 m.
Learn more about distance here: brainly.com/question/2854969
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The answer is B, because all energy is released at once in static electricity.
There’s a quizlet that mentions these questions, if you are having trouble. I’d suggest to give them a look.
Answer:
a.3.84m
b.-106.67m/s
c.947.3m/s^2
d.70.17 rad
e.2.5Hz
d.0.4secs
Explanation:
Given x=(7.8)cos[5πrad/s)t+π/3)]
a.Displacement at t=4.4
7.8cos(5π*4.4+π\3)=3.84m
b.velocity
V= dx/dr=-5π(7.8)sin(5πrad/s)t+π\3
at t=4.4
-5π(7.8)sin(5π*4.4+π\3)=-106.67m/s
c.acceleration
a=d^2x/dr^2
-(5π)^2(7.8) cos (5π*t+π\3)
at t=4.4
-(5π)^2(7.8)cos(5π*4.4+π\3)=-947.3m/s^2
d. Phase =(5πrad/s)t+π\3
At t=4.4
5π×4.4+π\3=70.17 rad
e.frequency
Given x= 7.8cos(5πt+π\3
Compare with x=Acos(2πft)
2πft=5πt
F=2.5Hz
f.T=1\f
T=1/2.5=0.4sec