The price of tomatoes went from $1.12 per pound to $1.96 per pound in 3 years. find the rate of change of the price of tomatoes.

1 answer:

7 0

$\bf \begin{array}{|cc|ll} \cline{1-2} \stackrel{x}{year}&\stackrel{y}{price}\\ \cline{1-2} 0&1.12\\ 3&1.96\\ \cline{1-2} \end{array}~\hspace{10em} (\stackrel{x_1}{0}~,~\stackrel{y_1}{1.12})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{1.96}) \\\\\\ \stackrel{\textit{rate of change}}{slope = m\implies} \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1.96-1.12}{3-0}\implies \cfrac{0.84}{3}\implies 0.28$

You might be interested in

Help please! this is due tomorrow so please help out! will mark as brainiest!!

lesya692 [45]

Answer:

$\large\boxed{\bold{Q1}\ -\dfrac{128}{9}}\\\boxed{\bold{Q2}\ 2^{25}}$

Step-by-step explanation:

$\bold{Q1}\\\\\dfrac{-2(3^2\cdot3^3)^2}{3^{12}\cdot2^{-6}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=-\dfrac{2(3^{2+3})^2}{3^{12}\cdot2^{-6}}=-\dfrac{2(3^5)^2}{3^{12}\cdot2^{-6}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=-\dfrac{2\cdot3^{5\cdot2}}{3^{12}\cdot2^{-6}}=-\dfrac{2\cdot3^{10}}{3^{12}\cdot2^{-6}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=-2^{1-(-6)}\cdot3^{10-12}=-2^{7}\cdot3^{-2}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=-2^7\cdot\dfrac{1}{3^2}=-\dfrac{2^7}{3^2}=-\dfrac{128}{9}$

$\bold{Q2}\\\\\dfrac{4^2}{4^{-7}}\cdot(2^4\cdot2^3)\cdot(3^{-2})^0\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m},\ a^n\cdot a^m=a^{n+m},\ a^0=1\\\\=4^{2-(-7)}\cdot2^{4+3}\cdot1=4^{9}\cdot2^7=(2^2)^{9}\cdot2^7\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=2^{2\cdot9}\cdot2^7=2^{18}\cdot2^7\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{18+7}=2^{25}$

5 0

3 years ago

How do i find the product and quotient 42.3 ÷ (-6)

Lyrx [107]

To get the product you have to times 42.3 by -6, which gives you 253.8.

If you are trying to find out the quotient then divide 42.3 by -6 which equals -7.05.

5 0

3 years ago

1/2×-7=1/3(×-12) solve

alexgriva [62]

Answer:

X=18

Step-by-step explanation:

(1/2)*x-7 = (1/3)*(x-12) // - (1/3)*(x-12)

(1/2)*x-((1/3)*(x-12))-7 = 0

(-1/3)*(x-12)+(1/2)*x-7 = 0

x/2-1/3*(x-12)-7 = 0

(-1/3*2*(x-12))/2+x/2+(-7*2)/2 = 0