Help!

Give an example of a mutation and explain how it could affect an organism? Your answer

ella [17]

Answer:

A mutation is a heritable change in the genetic material of an individual. The change can be large or small. Large changes involve the loss, addition, duplication, or rearrangement of whole chromosomes or chromosome segments. Mutations can affect an organism by changing its physical characteristics (or phenotype) or it can impact the way DNA codes the genetic information (genotype). When mutations occur they can cause termination (death) of an organism or they can be partially lethal.

Explanation:

8 0

3 years ago

Can u explain to me how to do this? This is my first time doing this type of question so explain or give me some of the answers

WITCHER [35]

Bruh bruh bruh bruh bruh bruh

5 0

3 years ago

Read 2 more answers

Order the following from smallest to largest

Dmitry [639]

1. Quark

2. Electron

3. Proton and Neutron

4. Nucleus

5. Atom

6. Molecule

8 0

3 years ago

Use this balanced equation to help you solve:

valentina_108 [34]

1. 842g of NaOH will form 547.3 g of Al(OH)₃

2. The yield is 93.55%

Explanation:

3NaOH + Al → Al(OH)₃ + 3Na

1.

Molar mass of NaOH = 40 g/mol

Molar mass of Al = 27 g/mol

Molar mass of Al(OH)₃ = 78 g/mol

According to the balanced equation:

3 moles of NaOH requires 1 mole of Al to form 1 mole of Al(OH)₃

The ratio of NaOH : Al : Al(OH)₃ = 3 : 1 : 1

3 X 40 g of NaOH reacts with 27 g of Al to form 78 g of Al(OH)₃

120 g of NaOH + 27g of Al → 78 g of Al(OH)₃

120g of NaOH form 78g of Al(OH)₃

1g of NaOH will form $\frac{78}{120}$ g of Al(OH)₃

842g of NaOH will form $\frac{78}{120} X 842 g$ of Al(OH)₃

= 547.3 g of Al(OH)₃

Therefore, 842g of NaOH will form 547.3 g of Al(OH)₃

2. Only 512 g of Al(OH)₃ is formed

Yield % = ?

$Yield = \frac{512}{547.3} X 100\\\\Yield = 93.55$

Therefore, the yield is 93.55%

5 0

3 years ago

A teacher gives a test to two algebra classes. The first class has 18 students, and the second has 24 students. If the average f

Morgarella [4.7K]

Answer:

The C) statement is true.

Explanation:

Let's call $x_1$ the average for the first class and $x_2$ the average for the second class. The overall average x is then:

$x=\frac{x_1*18+x_2*24}{18+24}\\x=\frac{84*18+x_2*24}{42}\\x=\frac{1512+x_2*24}{42}$

Since the average is given by $Average=\frac{Sum of all values}{Amount of values}$ . We can now calculate x assuming the maximun and minimun values of $x_2$ , 2400 (which is 100 times 24) and 0 respectivly. That gives:

$x=\frac{1512+2400}{42}\\x=93$

for it's maximun value and

$x=\frac{1512+0}{42}\\x=36$

for it's minimun value. So we get that x is between 36% and 93%.

5 0

3 years ago