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marusya05 [52]
3 years ago
6

If you have 10.0 grams of citric acid with enough baking soda (nahco3 how many moles of carbon dioxide can you produce?

Chemistry
2 answers:
kap26 [50]3 years ago
6 0
Easy stoichiometry conversion :)

So, for stoichiometry, we always start with our "given". In this case, it would be the 10.0 grams of NaHCO3. This unit always goes over 1.

So, our first step would look like this:

10.0
------
  1

Next, we need to cancel out grams to get to moles. To do this, we will do grams of citric acid on the BOTTOM of the next step, so it cancels out. This unit in grams will be the mass of NaHCO3, which is 84.007. Then, we will do our unit of moles on top. Since this is unknown, it will be 1.

So, our 2nd step would look like this:

1 mole CO2
-----------------
84.007g NaHCO3

When we put it together: our complete stoichiometry problem would look like this:

10.0g NaHCO3     1mol CO2
---------------------- x -------------------------
            1                  84.007g NaHCO3

Now to find our answer, all we need to do is:
Multiply the two top numbers together (which is 10.0)
Multiply the two bottom numbers together (Which is 84.007)

And then....

Divide the top answer by the bottom answer.

10.0/84.007 is 0.119

So, from 10.0 grams of citric acid, we have 0.119 moles of CO2.

Hope I could help!
alekssr [168]3 years ago
3 0

Answer : The number of moles of carbon dioxide is, 0.156 mole

Explanation : Given,

Mass of citric acid = 10 g

Molar mass of citric acid = 192 g/mole

The balanced chemical reaction will be,

C_6H_8O_7+3NaHCO_3\rightarrow Na_3C_6H_5O_7+3CO_2+3H_2O

From the balanced chemical reaction, we conclude that 1 mole of C_6H_8O_7 react with 3 moles of NaHCO_3 to give 1 mole of Na_3C_6H_5O_7, 3 moles of carbon dioxide gas and 3 moles of water as a product.

First we have to calculate the moles of citric acid.

\text{Moles of citric acid}=\frac{\text{Mass of citric acid}}{\text{Molar mass of citric acid}}=\frac{10g}{192g/mole}=0.052mole

Now we have to calculate the moles of carbon dioxide.

As, 1 mole of citric acid react to gives 3 moles of carbon dioxide

So, 0.052 mole of citric react to gives \frac{3}{1}\times 0.052=0.156 moles of carbon dioxide

Therefore, the number of moles of carbon dioxide is, 0.156 mole

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Answer:

The mass of the surrounding is M_t = 263.9 \ g

Explanation:

From the question we are told that

      The mass of  NaOH is  m = 13.9 \ g

      The mass of water is m_w = 250.0g

      The chemical equation for the dissociation process is

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         M_t = 263.9 \ g

The mass of the surround here is the mass of the coffee-cup calorimeter and this contain the mixture ( water and the NaOH ) so the mass of the surrounding is  

  M_t = 263.9 \ g

       

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