1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marusya05 [52]
3 years ago
6

If you have 10.0 grams of citric acid with enough baking soda (nahco3 how many moles of carbon dioxide can you produce?

Chemistry
2 answers:
kap26 [50]3 years ago
6 0
Easy stoichiometry conversion :)

So, for stoichiometry, we always start with our "given". In this case, it would be the 10.0 grams of NaHCO3. This unit always goes over 1.

So, our first step would look like this:

10.0
------
  1

Next, we need to cancel out grams to get to moles. To do this, we will do grams of citric acid on the BOTTOM of the next step, so it cancels out. This unit in grams will be the mass of NaHCO3, which is 84.007. Then, we will do our unit of moles on top. Since this is unknown, it will be 1.

So, our 2nd step would look like this:

1 mole CO2
-----------------
84.007g NaHCO3

When we put it together: our complete stoichiometry problem would look like this:

10.0g NaHCO3     1mol CO2
---------------------- x -------------------------
            1                  84.007g NaHCO3

Now to find our answer, all we need to do is:
Multiply the two top numbers together (which is 10.0)
Multiply the two bottom numbers together (Which is 84.007)

And then....

Divide the top answer by the bottom answer.

10.0/84.007 is 0.119

So, from 10.0 grams of citric acid, we have 0.119 moles of CO2.

Hope I could help!
alekssr [168]3 years ago
3 0

Answer : The number of moles of carbon dioxide is, 0.156 mole

Explanation : Given,

Mass of citric acid = 10 g

Molar mass of citric acid = 192 g/mole

The balanced chemical reaction will be,

C_6H_8O_7+3NaHCO_3\rightarrow Na_3C_6H_5O_7+3CO_2+3H_2O

From the balanced chemical reaction, we conclude that 1 mole of C_6H_8O_7 react with 3 moles of NaHCO_3 to give 1 mole of Na_3C_6H_5O_7, 3 moles of carbon dioxide gas and 3 moles of water as a product.

First we have to calculate the moles of citric acid.

\text{Moles of citric acid}=\frac{\text{Mass of citric acid}}{\text{Molar mass of citric acid}}=\frac{10g}{192g/mole}=0.052mole

Now we have to calculate the moles of carbon dioxide.

As, 1 mole of citric acid react to gives 3 moles of carbon dioxide

So, 0.052 mole of citric react to gives \frac{3}{1}\times 0.052=0.156 moles of carbon dioxide

Therefore, the number of moles of carbon dioxide is, 0.156 mole

You might be interested in
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is
Pie

Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

Step 5: Calculate the limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

7 0
3 years ago
PLEASE HELP QUICK AS POSSIBLE!!!!
GalinKa [24]

Answer:

4180J

Explanation:

(25.0g)(4.184J/g°C)(75°C-35.0°C)

(25.0g)(40.0°C)(4.184J/g°C)

(1.00*10³g°C)(4.184J/g°C) = 4184J

use sig figs:

4180J

8 0
3 years ago
QUESTION TWO
igomit [66]

Answer: The scientific method is an empirical method of acquiring knowledge that has characterized the development of science since at least the 17th century. It involves careful observation, applying rigorous skepticism about what is observed, given that cognitive assumptions can distort how one interprets the observation.

Explanation:

Hope this helps. :)

3 0
2 years ago
Balance this equation K+b2o3=k2o+b
AVprozaik [17]

Answer:

Explanation:

2K and 2b

5 0
2 years ago
When is the magnetic field the strongest?
Vadim26 [7]
The magnetic field<span> of a bar </span>magnet<span> is </span>strongest<span> at either pole of the </span>magnet<span>. It is equally strong at the north pole compared with the south pole. The force is weaker in the middle of the </span>magnet<span> and halfway between the pole and the center.</span>
8 0
3 years ago
Read 2 more answers
Other questions:
  • A solution contains 225 g of glucose, c6h12o6, dissolved in enough water to make 0.825 l of solution. what is the molarity of th
    8·1 answer
  • A sodium atom has 1 valence electron in its third shell. What will it do when forming an ion? A. gain 1 valence electron B. lose
    13·1 answer
  • How many square centimeters are in an area of 8.50 inch^2
    11·1 answer
  • How can you tell a Cu(No3)2 solution from a Ni(NO3)2 solution?
    10·1 answer
  • When 0.110 mol of aluminum are allowed to react with an excess of chlorine gas, Cl2, how many moles of aluminum chloride are pro
    5·1 answer
  • What are the coefficients that would balance the chemical equation below?
    10·1 answer
  • The molar mass of magnesium (Mg) is 24.30 g/mol. There are 6.02 Times. 1023 atoms in 1 mol.
    8·1 answer
  • If the solution is acidic, which ion is found in greater concentration?
    8·1 answer
  • What is true when a reaction has reached equilibrium?
    13·1 answer
  • How do you Calculate the molarity of 250 ml of solution in which 2.7 g of MgCl2 are dissolved
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!